06.06.2022 Views

B. P. Lathi, Zhi Ding - Modern Digital and Analog Communication Systems-Oxford University Press (2009)

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

7.2 Line Coding 337

Figure 7.7

Split-phase

(Manchester or

twinned-binary)

signal. (a) Basic

pulse p(t) for

Manchester

signaling.

(b) Transmitted

waveform for

binary data

sequence using

Manchester

signaling.

(a)

0 0 1 1 0 1 1 0 0 0 1 1 0

7 nmn mn nnmn r

WU UW UWULJ UW t--+-

I Tb I

(b)

we have

P(0) = i: p(t) dt

Hence, if the area under p(t) is made zero, P(0) is zero, and we have a de null in the PSD. For

a rectangular pulse, one possible shape of p (t) to accomplish this is shown in Fig. 7. 7 a. When

we use this pulse with polar line coding, the resulting signal is known as Manchester code, or

split-phase (also called twinned-binary), signal. The reader can use Eq. (7.13), to show that

for this pulse, the PSD of the Manchester line code has a de null (see Prob. 7.2-2).

7.2.4 On-Off Signaling

In on-off signaling, a 1 is transmitted by a pulse p(t) and a O is transmitted by no pulse. Hence,

a pulse strength ak is equally likely to be 1 or 0. Out of N pulses in the interval of T seconds,

ak is 1 for N /2 pulses and is O for the remaining N /2 pulses on the average. Hence,

1 N

Ro = lim - [

2 N 2

- (1) + (0) ] = -

1

N➔oo N 2 2 2

(7.16)

To compute R n we need to consider the product akak+n · Since ak and ak+n are equally likely

to be 1 or 0, the product akak+n is equally likely to be 1 x 1, 1 x 0, 0 x 1 or O x 0, that is,

1, 0, 0, 0. Therefore on the average, the product akak+n is equal to 1 for N /4 terms and O for

3N / 4 terms and

1 N 3N 1

[ ]

N➔oo N 4 4 4

R n

= lim -(1) + -(0) = -

n 2:: 1 (7.17)

Therefore, [Eq. (7.9)]

(7.1 8a)

(7 .18b)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!