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B. P. Lathi, Zhi Ding - Modern Digital and Analog Communication Systems-Oxford University Press (2009)

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770 INTRODUCTION TO INFORMATION THEORY

Fi g ure 13.7

Volume of a shell

of a

D-dimensional

hypersphere.

As direct consequence of this result, when D is large, almost all of the volume of the sphere

is concentrated at the surface. This is because if R/ R < I, then (R / R) D -+ 0 as D -+ oo.

This ratio approaches zero even if R differs from R by a very small amount b. (Fig. 13.7). This

means that no matter how small b. is, the volume within radius R is a negligible fraction of

the total volume within radius R if D is large enough. Hence, for a large D, almost all of the

volume of a D-dimensional sphere is concentrated at the surface. Such a result sounds strange,

but a little reflection will show that it is reasonable. This is because the volume is proportional

to the Dth power of the radius. Thus, for large D, a small increase in R can increase the volume

tremendously, and all the increase comes from a tiny increase in R near the surface of the

sphere. This means that most of the volume must be concentrated at the surface.

The number of nonoverlapping spheres of radius that can be packed into a sphere

of radius ✓ (S + N) T is bounded by the ratio of the volume of the signal sphere to the volume

of the noise sphere. Hence,

< [✓(S +N)T] 2BT V (l)

BT

M _

(

2BT - 1+ )

N

() V(l)

(13.67)

Each of the M -ary signals carries the information of log 2 M binary digits. Hence, the transmission

of one of the M signals every T seconds is equivalent to the information rate C

given by

(13.68)

This equation gives the upper limit of C.

To show that we can actually receive error-free information at a rate of Blog (1 + S /N),

we use the argument proposed by Shannon. 8 Instead of choosing the M transmitted messages

at the centers of nonoverlapping spheres (Fig. 13.6b), Shannon proposed selecting the M

points randomly located in the signal sphere l s of radius ,/sf (Fig. 13.8). Consider one

particular transmitted signal sk - Because the signal energy is assumed to be :S S, point sk

will lie somewhere inside the signal sphere l s of radius Jsf. Because all the M signals are

picked randomly from this sphere, the probability of finding a signal within a volume b. V is

min(l, Mb. V /V,), where V s is the volume of 1, . But because for large D all of the volume

of the sphere is concentrated at the surface, all M signal points selected randomly would lie

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