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B. P. Lathi, Zhi Ding - Modern Digital and Analog Communication Systems-Oxford University Press (2009)

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402 FUNDAMNTALS OF PROBABILITY THEORY

The reception of each digit is independent of the other digits. This is an example of a

Bernoulli trial with the probability of success p = P e ("success" here is receiving a digit

in error). Clearly, the probability of k successes in n trials (k errors in n digits) is

P(receiving k out of n digits in error) = G) P! (l - P e )"-k

For example, if P e = 10- 5 , the probability of receiving two digits wrong in a sequence

of eight digits is

Example 8.7

PCM Repeater Error Probability

In pulse code modulation, regenerative repeaters are used to detect pulses (before they are lost

in noise) and retransmit new, clean pulses. This combats the accumulation of noise and pulse

distortion.

A certain PCM channel consists of n identical links in tandem (Fig. 8.3). The pulses are

detected at the end of each link and clean new pulses are transmitted over the next link. If P e

is the probability of error in detecting a pulse over any one link, show that PE, the probability

of error in detecting a pulse over the entire channel (over the n links in tandem), is

nP e « 1

Figure 8.3

A PCM repeater.

1st link 2st link kth link

In ----------.-.---+----e--- - - - -.-.-------------- Out

The probabilities of detecting a pulse correctly over one link and over the entire channel

(n links in tandem) are 1 - P e and 1 - PE , respectively. A pulse can be detected correctly

over the entire channel if either the pulse is detected correctly over every link or errors

are made over an even number of links only.

1 - PE = P(correct detection over all links)

+ P(error over two links only)

+ P(error over four links only) + •••

+ P(error over 2 lJ links only)

where LaJ denotes the largest integer less than or equal to a.

Because pulse detection over each link is independent of the other links (see Example 8.6),

P(correct detection over all n links) = (1 - P et

and

n!

P(error over k links only) = P! (1 - P e ) n -k

k!(n - k)!

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