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formed, as shown <strong>in</strong> API Compendium Equation 5-9. For this example, the chemical reaction for each<br />

compound is:<br />

CH 4 : CH 4 + 2H 2 O = 4H 2 + 1CO 2<br />

C 2 H 6 : C 2 H 6 + 4H 2 O = 7H 2 + 2CO 2<br />

C 4 H 10 : C 4 H 10 + 8H 2 O = 13H 2 + 4CO 2<br />

For this approach, the moles of carbon <strong>and</strong> hydrogen are determ<strong>in</strong>ed by multiply<strong>in</strong>g the number of molecules<br />

of each <strong>in</strong> each compound by the composition of each compound <strong>in</strong> the feed <strong>gas</strong> (i.e., CH 4 , C 2 H 6 , <strong>and</strong> C 4 H 10 ).<br />

These results are used to determ<strong>in</strong>e the ratio of moles of carbon to moles of H 2 , <strong>and</strong> are shown <strong>in</strong> Table 5-7.<br />

Table 5-7. Hydrogen <strong>and</strong> Carbon Composition Data<br />

Compound<br />

# C<br />

Atoms<br />

# H 2<br />

Molecules Concentration<br />

Comb<strong>in</strong>ed<br />

Uncerta<strong>in</strong>ty (rel)<br />

(mole%) Moles C Moles H 2<br />

CH 4 1 4 0.85 5.00% 0.85 3.4<br />

C 2 H 6 2 7 0.08 5.22% 0.16 0.56<br />

C 4 H 10 4 13 0.03 6.01% 0.12 0.39<br />

Total Moles 1.13 4.35<br />

Sum <strong>uncerta<strong>in</strong>ty</strong><br />

(abs)<br />

0.0439 0.0439<br />

Sum <strong>uncerta<strong>in</strong>ty</strong><br />

(rel)<br />

3.89% 3.89%<br />

The carbon-to-hydrogen ratio is calculated by divid<strong>in</strong>g the total moles C by the total moles H 2 (1.13/4.35 =<br />

0.26). S<strong>in</strong>ce each mole of carbon produces 1 mole of CO 2 , the CO 2 /H 2 ratio is the<br />

same as the C/H 2 ratio (0.26).<br />

The <strong>uncerta<strong>in</strong>ty</strong> associated with the total moles of C <strong>and</strong> H 2 is calculated by apply<strong>in</strong>g Equation 4-4, us<strong>in</strong>g the<br />

absolute uncerta<strong>in</strong>ties of each molar compound.<br />

∑<br />

2<br />

U ( abs) = U ( abs)<br />

( C)<br />

mole C<br />

∑ mole<br />

U ( abs) = (0.0500× 0.85) + (0.0522× 0.08) + (0.0601×<br />

0.03)<br />

∑( mole C)<br />

U ( abs) = 0.0439<br />

∑( mole C)<br />

0.0439<br />

Urel ( ) = × 100% = 3.89%<br />

∑( mole C)<br />

1.13<br />

∑<br />

2 2 2<br />

2<br />

U ( abs) = U ( abs)<br />

( H H<br />

2 )<br />

mole<br />

∑ mole<br />

2<br />

U ( abs) = (0.0500× 3.4) + (0.0522× 0.53) + (0.0601×<br />

0.39)<br />

∑( mole H 2 )<br />

U ( abs) = 0.1742<br />

∑( mole H 2 )<br />

0.1742<br />

Urel ( ) = × 100% = 4.00%<br />

∑( mole H 2 )<br />

4.35<br />

2 2 2<br />

Pilot Version, September 2009 5-17

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