Electrodynamic loads* and dead weight po<strong>in</strong>t No.1 po<strong>in</strong>t No.2 po<strong>in</strong>t No.3 Fx 29 N 20 N 9 N Fy* -1290 N 557 N 733 N Fz -4034 N -4034 N -4034 N Mx* 2989 N.m -1337 N.m -1652 N.m My 1457 N.m 1437 N.m 1412 N.m Mz* -1463 N.m 695 N.m 768 N.m <strong>The</strong> location <strong>of</strong> po<strong>in</strong>ts 1, 2, 3 is shown on the Figure 2.18. Newton meter Newton meter Newton meter 4000 3000 2000 1000 0 -1000 -2000 -3000 -4000 1500 1400 1300 1200 1100 1000 0,00 0,00 2000 1500 1000 500 0 -500 -1000 -1500 -2000 0,00 0,03 0,03 0,03 0,06 0,06 0,06 0,10 0,10 0,10 0,13 0,13 0,13 Column po<strong>in</strong>t 1 Column spacer Moments to x 0,16 0,19 0,23 time <strong>in</strong> s 0,31 Moments to y 0,16 0,19 0,23 time <strong>in</strong> s 0,31 Moments to z 0,16 0,19 0,23 time <strong>in</strong> s 0,39 0,39 po<strong>in</strong>t 2 Figure 2.19 Forces and moments at bottom <strong>of</strong> the column 0,31 0,39 0,47 0,47 0,47 30 Support element <strong>in</strong>ternal stresses N/m² ICC ICC+ PP Column 1.32 e7 1.37 e8 Column spacers 1 e7 7.5 e7 Beam 1.65 e7 1.29 e8 Beam spacers 2.27 e5 1.71 e7 Post <strong>in</strong>sulator support spacers 8.94 e6 1.69 e8 Beamspacer Post <strong>in</strong>sulator support spacer po<strong>in</strong>t 3 Force Figure 2.18 Location <strong>of</strong> forces and moments 0,55 0,55 0,55 Phase 1 Phase 2 Phase 3 Sum phase 1 Phase 2 Phase 3 phase 1 Phase 2 Phase 3 Sum Newton Newton Newton 100 80 60 40 20 0 -20 -40 -60 -80 0,00 1500 1000 500 0 -500 -1000 -1500 -3500 -4000 -4500 0,00 0,00 0,03 0,03 0,03 Moment 0,06 0,07 0,07 0,09 0,10 0,10 0,12 0,15 0,14 0,14 Forces to x 0,18 0,21 time <strong>in</strong> s 0,27 0,35 Forces to y 0,17 0,20 time <strong>in</strong> s 0,27 0,35 Forces to z 0,17 0,20 time <strong>in</strong> s 0,27 0,35 0,42 0,44 0,44 0,50 0,52 0,52 0,57 phase 1 Phase 2 Phase 3 Sum phase 1 Phase 2 Phase 3 Sum phase 1 Phase 2 Phase 3
2.3.2. Influence <strong>of</strong> two busbars a) Introduction Many substations have several busbars <strong>in</strong> parallel. To handle three-phase or phase to phase faults on 1 or 2 busbars, a special analyses is done <strong>in</strong> this section to approach the maximum amplitude <strong>of</strong> stresses to def<strong>in</strong>e the withstand<strong>in</strong>g capability <strong>of</strong> the structures. For example, RTE takes the follow<strong>in</strong>g fault situation named « transfer situation » <strong>in</strong>to account when only one l<strong>in</strong>e is temporarily protected by the « coupl<strong>in</strong>g bay » protections : Figure 2.20 Two busbars <strong>in</strong> parallel An amplification coefficient is <strong>in</strong>troduced which allows one to step from a reference situation to the actual configuration depend<strong>in</strong>g on the type <strong>of</strong> substation (separated or associated phase layout) and <strong>of</strong> the fault to be analysed. This approach gives also the maximum asymmetry for these cases. b) General considerations <strong>The</strong> amplitude <strong>of</strong> the LAPLACE’s force depends on the location <strong>of</strong> the considered phase, the type <strong>of</strong> fault and the characteristic <strong>of</strong> the fault. Phase to phase fault and phase to earth fault Due to the l<strong>in</strong>ear properties <strong>of</strong> the <strong>mechanical</strong> equations, the maximum <strong>of</strong> the force correspond<strong>in</strong>g to the maximum asymmetry is obta<strong>in</strong>ed when the phase voltage is zero at the beg<strong>in</strong>n<strong>in</strong>g <strong>of</strong> the fault. <strong>The</strong> amplification coefficients are given below and are without approximation. Three-phase fault If the <strong>in</strong>stant expression <strong>of</strong> LAPLACE’s force is given by an expression <strong>of</strong> the type : µ 2π let us suppose that : 0 (2.81) F = . i . ( α. i + β. i + γ . i ) (2.82) K = α. a + β + γ. a = K . e where a = e 2 2 1 j. Φ In this paragraph, Re(K) is the real part <strong>of</strong> K. 2 3 2π j 3 <strong>The</strong> maximum force is reached after ½ period and its value is : 31 ) µ 0 F = . Ik′′ . 2π (2.83) ) µ 0 F = . Ik′′ . 2π (2.84) ( 2. κ) ⎛ 2⎛Φ ⎞ 2⎛Φ ⎞⎞ . K . MAX ⎜ ⎜cos ⎜ ⎟, s<strong>in</strong> ⎜ ⎟ 2 2 ⎟ ⎝ ⎝ ⎠ ⎝ ⎠⎠ 2 2 K + Re( K) ( 2. κ) . 2 −3R X κ = 1. 02 + 0. 98e κ : factor for the calculation <strong>of</strong> the peak <strong>short</strong><strong>circuit</strong> current [Ref 11]. <strong>The</strong> ma<strong>in</strong> steps which allow one to obta<strong>in</strong> this relation are given <strong>in</strong> [Ref 99]. <strong>The</strong> solution to this problem seem<strong>in</strong>gly allows the ma<strong>in</strong> situations met to be handled (separated phases and associated phases . . .). <strong>The</strong> amplification coefficient <strong>in</strong> this case is not exact because this optimization is done on the force not on the dynamic response <strong>of</strong> the system. All components def<strong>in</strong>ed <strong>in</strong> paragraph 2.2 <strong>of</strong> Ref 1 are taken <strong>in</strong>to account same as <strong>in</strong> the IEC standard. <strong>The</strong> dynamic behavior can differ likely like for the central busbar for an associated-phase layout <strong>in</strong> a three-phase fault <strong>in</strong> comparison with this optimization [Ref 8]. If the reference situation is calculated with an advanced method tak<strong>in</strong>g <strong>in</strong>to account time constant and fault clearance time, the amplification coefficient is applied to the maximum Freference. (2.85) ) F = F . xb reference Kxp <strong>The</strong> tables given below can be used to f<strong>in</strong>d the maximum <strong>of</strong> asymmetry on a bar dur<strong>in</strong>g a threephase fault on two busbars. This asymmetry is given on phase 1 <strong>of</strong> the busbar 1. c) Laplace’s force due to the <strong>short</strong>-<strong>circuit</strong> <strong>The</strong>re are three possible layouts : - separate-phase layout, - asymmetrical associated-phase layout, - symmetrical associated-phase layout. For the separate-phase layout, the maximum LAPLACE force named reference <strong>in</strong> Table 2.5 is given by : (2.86) F reference µ 0 = 2π " ( I 2κ ) k1 correspond<strong>in</strong>g to a phase to earth fault <strong>in</strong> transfer situation. For the associated-phase layouts, the maximum LAPLACE force named reference <strong>in</strong> Table 2.6 and Table 2.7 is given by : (2.87) F reference µ 0 = 2π d 2 " 2 ( I k 2κ ) 3 d 4 correspond<strong>in</strong>g to a phase to phase fault on one busbar. Both these values can be calculated by advanced methods.
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5.2.2. A global Approach For analyz
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to multinode operation can compared
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5.2.3.1.7. Proposed Approach The st
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The first case (Figure 5.14) corres
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centers are normally balanced by ba
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Remark: The risk integral (5.3) can
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1,0 0,8 0,6 0,4 0,2 0,0 -0,2 -0,4 -
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The histograms below for the instan
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5.2.3.8.2. Reliability based design
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power converter in a three phase br
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The time functions of the currents
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a) Determination of the linear mome
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Figure 6.11 Coefficients mJs1 and m
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7. REFERENCES Ref 1. IEC TC 73/CIGR
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Ref 42. Stein, N.; Miri, A.M.; Meye
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Ref 80. Fiabilité des structures d
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8. ANNEX 8.1. THE EQUIVALENT STATIC
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Figure 8.2 What is ESL in this case
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As the eigenfrequency of the portal
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Figure 8.9 Case 3 (third eigenfrequ
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Both cases have the same 200-kV-arr
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a) c) 5 +25 % 0 % 4 3 F c / F st 2
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a) b) 24 kN 20 +25 % 0 % 2,0 m F c
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Case *11 (EDF 1990) This is the 102
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( ( δ ) ( δ ) ) T = Mg08 . b r .
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IEC 60865 Calculations If the clear
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f) Calculation of the stresses due
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d) Determination of the forces at t
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8.7. ERRATA TO BROCHURE NO 105 In V