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Tuyển chọn các dạng toán hay lạ khó - Chu Văn Biên (Phần I-IV)

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P2 9P1 I2 3I1<br />

ZL<br />

3Z<br />

Ta thấy: <br />

<br />

3<br />

ZC<br />

ZC<br />

2<br />

<br />

<br />

3<br />

2 L1<br />

2 1 1<br />

<br />

Vẽ giản đồ véctơ: i 1 sớm pha hơn u; i 2 trễ pha hơn u; Vì I I nên tứ giác AM 1 BM 2<br />

là hình chữ nhật.<br />

1 2<br />

Ta có hệ:<br />

U LC1 U<br />

R2 I1( ZC1 ZL<br />

1)<br />

I2R<br />

<br />

U LC 2<br />

U<br />

R1 I2( ZL2 ZC<br />

2)<br />

I1R<br />

I1( ZC1 ZL<br />

1) 3I1R<br />

<br />

ZC1<br />

3 I1(3 ZL<br />

1<br />

) I1R<br />

3<br />

Câu 11.<br />

Z<br />

<br />

Z<br />

L1<br />

C1<br />

0,5R<br />

3,5R<br />

Chọn C, D.<br />

Vì U 2L = 6U 1L nên U 2R = 6U 1R . Đặt U 1R = x thì U 2R = 6x.<br />

UR1<br />

arccos<br />

1<br />

U<br />

Theo bài ra: a 114 <br />

1 2<br />

<br />

UR<br />

2<br />

a2<br />

arccos<br />

U<br />

x 6x<br />

arccos arccos 114 x 21,17( V ) Chọn B.<br />

150 150

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