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Tuyển chọn các dạng toán hay lạ khó - Chu Văn Biên (Phần I-IV)

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Cách 2: Dùng giản đồ NAV, trường hợp này ∆φ = 2π/3.<br />

Từ:<br />

U R2 3U R1<br />

3a<br />

U RL2 3U RL1 I2 3I1<br />

<br />

<br />

U L2 3U L1<br />

3b<br />

<br />

<br />

ZC1<br />

3 U<br />

<br />

C2 2C1 ZC 2<br />

UC 2<br />

UC1<br />

<br />

<br />

2 2 U<br />

C1<br />

C 2<br />

2c<br />

3c<br />

*Từ M2AM 1:<br />

U<br />

2 2<br />

M1M<br />

U<br />

2 R1 U R2 2U R1U<br />

R2<br />

cos <br />

2a<br />

39<br />

<br />

sin <br />

sin <br />

3<br />

3U<br />

a <br />

2 39<br />

<br />

2 2<br />

7a<br />

3<br />

U<br />

LC1 U U R1<br />

2c b <br />

<br />

3<br />

<br />

2 2<br />

5a<br />

3<br />

U<br />

LC 2<br />

U U R2<br />

3b 3c<br />

<br />

<br />

3<br />

26a<br />

3<br />

c <br />

9<br />

<br />

31a<br />

3 31U<br />

13<br />

b <br />

9 78<br />

2 2 2<br />

URL1U R1U<br />

L1<br />

3U<br />

31U<br />

13<br />

URL140; U R1a ; UL1b<br />

2 39<br />

78<br />

U 27,53 U0 U 2 38,93( V ) <br />

Chọn B.<br />

Câu 19.<br />

Ta thấy:<br />

<br />

U<br />

R2 3U<br />

R1<br />

U<br />

RL2 3U RL1 I2 3I1<br />

<br />

<br />

U<br />

L2 3U<br />

L1<br />

<br />

<br />

<br />

ZC1<br />

3<br />

C2 2 C1 ZC 2<br />

UC 2<br />

UC1(*)<br />

<br />

2 2<br />

<br />

U<br />

U<br />

R1 R2<br />

UR13U<br />

R 2 R1<br />

120 arccos arccos 120<br />

<br />

U U<br />

U<br />

R2<br />

U<br />

<br />

0,24U<br />

0,72U

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