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Metode Numerik 2 - Universitas Indonesia

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116<br />

Untuk mendapatkan rumus metode Runge-Kutta orde 4, orang bisa memulai<br />

dengan mengevaluasi integral f(x,y) memakai quadrature Simpson:<br />

x + h<br />

0<br />

∫<br />

x<br />

0<br />

dengan:<br />

f(x, y)dx ≅<br />

f<br />

0<br />

≅<br />

1<br />

6<br />

1<br />

6<br />

h<br />

h<br />

= f(x<br />

f = f(x<br />

1<br />

1<br />

1<br />

[ f(x , y ) + 4f(x + h, y(x + h)) + f(x + h, y(x + h)) ]<br />

( f + 2f + 2f + f )<br />

0<br />

0<br />

0<br />

, y<br />

+<br />

0<br />

1<br />

2<br />

0<br />

)<br />

1<br />

0<br />

h, y(x<br />

0<br />

2<br />

+<br />

1<br />

2<br />

3<br />

0<br />

h))<br />

1<br />

f1 dan f2<br />

memiliki nilai berbeda, karena dihitung untuk nilai argumen y(x0 + 2 h)<br />

1<br />

yang berbeda: menurut metode Euler, y(x0 h) 2 dapat diperoleh melalui 2<br />

persamaan:<br />

+<br />

2<br />

f<br />

2<br />

f<br />

3<br />

0<br />

= f(x<br />

= f(x<br />

0<br />

0<br />

2<br />

+<br />

1<br />

2<br />

h, y(x<br />

+ h, y(x<br />

0<br />

0<br />

0<br />

+<br />

1<br />

2<br />

+ h))<br />

(1)<br />

atau<br />

1<br />

1<br />

y(x0<br />

+ 2 h) ≅ y0<br />

+ 2 hf0<br />

1<br />

1<br />

f1<br />

= f(x0<br />

+ 2 h, y0<br />

+ 2 hf0<br />

)<br />

(2)<br />

y<br />

0<br />

≅<br />

≅<br />

y(x<br />

y(x<br />

0<br />

y(x<br />

0<br />

0<br />

+<br />

+<br />

+<br />

1<br />

2<br />

1<br />

2<br />

1<br />

2<br />

h) −<br />

h) −<br />

h) ≅<br />

1<br />

2<br />

1<br />

2<br />

y<br />

hf(x<br />

hf(x<br />

0<br />

+<br />

1<br />

2<br />

0<br />

0<br />

+<br />

+<br />

hf<br />

1<br />

1<br />

2<br />

1<br />

2<br />

h, y(x<br />

h, y<br />

0<br />

0<br />

+<br />

+<br />

1<br />

2<br />

f<br />

2<br />

1<br />

2<br />

hf<br />

h))<br />

0<br />

)<br />

= f(x<br />

0<br />

+<br />

1<br />

2<br />

h, y<br />

h))<br />

0<br />

+<br />

1<br />

2<br />

0<br />

hf)<br />

1

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