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Metode Numerik 2 - Universitas Indonesia

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Interpolasi Spline Kubik<br />

Seperti interpolasi Lagrange, interpolasi Spline kubik juga memerlukan hanya<br />

f(x) sebagai data. Namun, turunan fungsi interpolasi Spline kubik p’(x) dibuat<br />

bersifat kontinyu.<br />

Interpolasi Spline kubik menggunakan polinomial p(x) orde 3, untuk x :<br />

i ≤ x ≤ xi+<br />

1<br />

p(x) = d + c (x − x ) + b(x<br />

− x )<br />

Turunan pertama dan kedua p(x) yaitu:<br />

i<br />

i<br />

p'(x)<br />

p''(x)<br />

i<br />

i<br />

= 2b + 6a (x − x )<br />

Evaluasi pada titik x = x menghasilkan:<br />

dan pada titik x = x : i+<br />

1<br />

i<br />

i<br />

i<br />

i<br />

2<br />

+ a (x − x )<br />

= c + 2b (x − x ) + 3a (x − x )<br />

i<br />

i<br />

i<br />

i<br />

i<br />

i<br />

p ≡ p(x ) = d = f(x ) p''<br />

≡ p''(x<br />

) = 2b<br />

i<br />

i<br />

i<br />

i<br />

i<br />

i<br />

i<br />

i<br />

2<br />

3<br />

≅ f(x)<br />

2 3<br />

i+<br />

1 ≡ p''(xi<br />

+ 1)<br />

= 2bi<br />

+ 6aihi<br />

pi+<br />

1 ≡ p(xi+<br />

1)<br />

= di<br />

+ cihi<br />

+ bihi<br />

+ aihi<br />

= f(xi+<br />

1)<br />

hi<br />

≡ xi+<br />

1<br />

p'' − x<br />

i<br />

i<br />

73

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