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Metode Numerik 2 - Universitas Indonesia

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Untuk f , digunakan metode Euler yang dimodifikasi untuk mencari y(x0 + h) :<br />

Jadi, menurut metode Runge-Kutta orde 4:<br />

dengan:<br />

3<br />

y(x<br />

0<br />

+ h) ≅<br />

f<br />

0<br />

= f(x<br />

f = f(x<br />

1<br />

≅<br />

≅<br />

y<br />

y<br />

0<br />

0<br />

y<br />

0<br />

0<br />

0<br />

+ hf(x<br />

+ hf(x<br />

+ hf<br />

0<br />

0<br />

1<br />

6<br />

( f + 2f + 2f f )<br />

y(x + h) = y + h<br />

+<br />

, y<br />

+<br />

0<br />

1<br />

2<br />

)<br />

2<br />

h, y<br />

0<br />

0<br />

0<br />

+<br />

+<br />

+<br />

1<br />

2<br />

1<br />

2<br />

1<br />

2<br />

h, y(x<br />

h, y<br />

hf<br />

0<br />

0<br />

)<br />

+<br />

0<br />

1<br />

2<br />

+<br />

hf)<br />

0<br />

1<br />

2<br />

f<br />

2<br />

f<br />

3<br />

1<br />

h))<br />

1<br />

= f(x<br />

= f(x<br />

f<br />

0<br />

0<br />

3<br />

= f(x<br />

+<br />

2<br />

1<br />

2<br />

+ h, y<br />

3<br />

h, y<br />

0<br />

0<br />

+ h, y<br />

0<br />

+<br />

1<br />

2<br />

+ hf )<br />

2<br />

0<br />

hf)<br />

1<br />

+ hf )<br />

2<br />

117

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