01.06.2015 Views

Actuarial Modelling of Claim Counts Risk Classification, Credibility ...

Actuarial Modelling of Claim Counts Risk Classification, Credibility ...

Actuarial Modelling of Claim Counts Risk Classification, Credibility ...

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

<strong>Actuarial</strong> Analysis <strong>of</strong> the French Bonus-Malus System 339<br />

giving the reduced penalty in case <strong>of</strong> a partial liability claim. Now the CRM coefficient for<br />

the time period 0t is<br />

with<br />

r t t t<br />

N 1• N 2• I 12• t= 1 + t N 1•<br />

1 + t N 2•<br />

1 − t I 12•<br />

N 1• =<br />

N 2• =<br />

I 12• =<br />

t∑<br />

N 1j<br />

j=1<br />

t∑<br />

N 2j<br />

j=1<br />

t∑<br />

j=1<br />

{ 1ifN1j = N<br />

I j with I j =<br />

2j = 0<br />

0 otherwise<br />

We will assume that t = t with fixed by the actuary. The value <strong>of</strong> describes the way<br />

a claim with full liability is penalized, compared to a claim with partial liability. Then the<br />

CRM coefficient becomes<br />

r t t<br />

N 1• N 2• I 12• t= 1 + t N 1•<br />

1 + t N 2•<br />

1 − t I 12•<br />

<br />

In order to obtain t and t we have now to minimize the objective function<br />

t = [( − r N 1• N 2• I 12• t ) 2]<br />

with respect to the parameters and . The first order conditions are<br />

⎧<br />

[ (<br />

1 − I 12• N1• 1 + N1•−1 1 + N 2• + N2• 1 + N2•−1 1 + 1•)]<br />

N<br />

⎪⎨<br />

= [ (<br />

1 − 2I 12• N1• 1 + 2N1•−1 1 + 2N 2• + N2• 1 + 2N2•−1 1 + 1•)]<br />

2N<br />

[ 1 + N 1• 1 + <br />

N 2•I12• 1 − I 12•−1 ]<br />

⎪⎩<br />

= [ 1 + 2N 1• 1 + <br />

2N 2•I12• 1 − ] 2I 12•−1<br />

<br />

Let us define<br />

[<br />

1 2 3 = N 1•<br />

1 N 2•<br />

2 I 12•<br />

3<br />

]<br />

∣<br />

∣ = <br />

to be the conditional probability generating function <strong>of</strong> the random vector N 1• N 2• I 12• <br />

given = . We clearly have that<br />

( ))<br />

1 2 3 =<br />

(e − 3 − 1 + e 1−q 1 +q 2 −1 t

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!