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Actuarial Modelling of Claim Counts Risk Classification, Credibility ...

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16 <strong>Actuarial</strong> <strong>Modelling</strong> <strong>of</strong> <strong>Claim</strong> <strong>Counts</strong><br />

for = nq to be small. It is the largeness <strong>of</strong> n and the smallness <strong>of</strong> q = /n that are<br />

important. However most <strong>of</strong> the data sets analysed in the literature show a small frequency.<br />

This will be the case with motor data sets in insurance applications.<br />

Moments <strong>of</strong> the Poisson Distribution<br />

If N ∼ oi, then its expected value is given by<br />

Moreover,<br />

EN =<br />

+∑<br />

k=1<br />

= exp−<br />

k exp− k<br />

k!<br />

+∑ k+1<br />

k=0<br />

k!<br />

= (1.14)<br />

EN 2 =<br />

+∑<br />

k=1<br />

so that the variance <strong>of</strong> N is equal to<br />

= exp−<br />

k 2 exp− k<br />

k!<br />

+∑<br />

k=0<br />

k + 1 k+1<br />

= + 2 <br />

k!<br />

VN = EN 2 − 2 = (1.15)<br />

Considering Expressions (1.14) and (1.15), we see that both the mean and the variance <strong>of</strong><br />

the Poisson distribution are equal to , a phenomenon termed as equidispersion.<br />

The skewness <strong>of</strong> N ∼ oi is<br />

N = √ 1 (1.16)<br />

<br />

Clearly, N decreases with . For small values <strong>of</strong> the distribution is very skewed<br />

(asymmetric) but as increases it becomes less skewed and is nearly symmetric by = 15.<br />

Probability Generating Function and Closure Under Convolution for the<br />

Poisson Distribution<br />

The probability generating function <strong>of</strong> the Poisson distribution has a very simple form.<br />

Coming back to the Equation (1.5) defining N and replacing the p k s with their expression<br />

(1.13) gives<br />

+∑<br />

N z = exp− zk = exp ( z − 1 ) (1.17)<br />

k=0<br />

k!<br />

This shows that the Poisson distribution is closed under convolution. Having independent<br />

random variables N 1 ∼ oi 1 and N 2 ∼ oi 2 , the probability generating function <strong>of</strong><br />

the sum N 1 + N 2 is<br />

N1 +N 2<br />

z = N1<br />

z N2<br />

z = exp ( 1 z − 1 ) exp ( 2 z − 1 ) = exp ( 1 + 2 z − 1 )<br />

so that N 1 + N 2 ∼ oi 1 + 2 .

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