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650 S. Albeverio, A. Kosyak / Journal of Functional Analysis 236 (2006) 634–681<br />

<br />

<br />

<br />

+ <br />

exp<br />

<br />

r<br />

l=1<br />

s (n)<br />

l Aln<br />

<br />

Aqn − xpqDpn +<br />

m<br />

k=1,k=q<br />

α (n)<br />

k Akn<br />

where we have used the equality ξ − Mξ 2 =ξ 2 −|Mξ| 2 :<br />

<br />

<br />

<br />

r<br />

<br />

Dpn exp<br />

<br />

l=1<br />

s (n)<br />

l Aln<br />

<br />

− Mξ rp<br />

(n)<br />

n s <br />

<br />

<br />

<br />

1<br />

<br />

<br />

2<br />

<br />

1<br />

,<br />

<br />

=Dpn1 2 − rp<br />

(n)<br />

Mξn s 2 = c (n)<br />

pp − rp<br />

(n)<br />

Mξn s 2 .<br />

Definition. We shall say that two series <br />

n an and <br />

n bn with positive members are equiva<strong>le</strong>nt<br />

and shall <strong>de</strong>note this by <br />

n an ∼ <br />

n bn if they are convergent or divergent simultaneously. We<br />

note that if an > 0, bn > 0, n ∈ N, then we have<br />

an<br />

∼ an<br />

. (13)<br />

min<br />

t∈R N<br />

an + bn<br />

n∈N<br />

bn<br />

n∈N<br />

Using (5) we get, setting b = (Mξ rp<br />

n (s (n) )) m+1+N<br />

n=m+1 ∈ RN , N ∈ N,<br />

∼<br />

m+1+N<br />

<br />

n=m+1<br />

m+1+N<br />

<br />

n=m+1<br />

<br />

r<br />

tn exp s<br />

l=1<br />

(n)<br />

l Aln<br />

<br />

m<br />

α<br />

k=1<br />

(n)<br />

k Akn<br />

<br />

2<br />

<br />

<br />

<br />

− xpq 1<br />

(t, b) =−1<br />

<br />

|Mξ rp<br />

n (s (n) )| 2<br />

c (n)<br />

pp −|Mξ rp<br />

n (s (n) )| 2 +(Aqn − xpqDpn + m k=1,k=p α (n)<br />

2<br />

k<br />

Akn)1 2<br />

−1<br />

. ✷<br />

DuetoRemark9weshallwriteC (respectively Ĉ) instead of C (n) (respectively Ĉ (n) ), where<br />

⎛<br />

Ĉ (n) ⎜<br />

= ⎜<br />

⎝<br />

c (n)<br />

11<br />

c (n)<br />

12<br />

c (n)<br />

1m<br />

⎛<br />

C (n) ⎜<br />

= ⎜<br />

⎝<br />

c (n)<br />

11<br />

c (n)<br />

11<br />

c (n)<br />

12<br />

c (n)<br />

1m c(n)<br />

2m<br />

c (n)<br />

12 ... c (n)<br />

1m<br />

c (n)<br />

22 ... c (n)<br />

⎞<br />

⎟<br />

2m ⎟<br />

.<br />

⎟<br />

.. ⎠ ,<br />

... c(n)<br />

mm<br />

c (n)<br />

12 ... c (n)<br />

+ c(n)<br />

22 ...<br />

1m<br />

c (n)<br />

. ..<br />

2m<br />

c (n)<br />

2m ... c (n)<br />

11 + c(n)<br />

22 +···+c(n)<br />

⎞<br />

⎟<br />

⎠<br />

mm<br />

.<br />

Remark 14. To simplify the further computations we assume that the mea<strong>sur</strong>es μ B (n) for 2 <br />

n m are standard: B (n) = I . Since μ m B = ∞ n=2 μ B (n) this assumption, which only concerns<br />

finitely many of the μ B (n)’s, does not change the equiva<strong>le</strong>nce c<strong>la</strong>ss of the initial mea<strong>sur</strong>e μ m B and<br />

the equiva<strong>le</strong>nce c<strong>la</strong>ss of the corresponding representation T R,μm B .

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