integration of solid oxide fuel cells and ... - Ea Energianalyse
integration of solid oxide fuel cells and ... - Ea Energianalyse
integration of solid oxide fuel cells and ... - Ea Energianalyse
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C. EES<br />
C.2 Results - St<strong>and</strong>ard parameter configuration<br />
ABSO c;i = 36 ABSO c;o = 37<br />
ABSO r ;i = 54 ABSO s;i = 62<br />
ABSO s;o = 55<br />
AddPreHeat$ = ‘On’<br />
Air Fuel Ratio;m = 92,78 [-] Air Fuel Ratio;n = 8,355 [-]<br />
Air i = 11 [-] α SPG1 = 0,62 [-]<br />
α SPG2 = 0,0461 [-]<br />
ASR = 0,00005542 [ Ω·m 2] α SPL1 = 0,4351 [-]<br />
A cell = 0,0228 [ m 2]<br />
BLOW 1 i = 11 BLOW 1 o = 12<br />
Bur n i ;1 = 10 [-] Bur n i ;2 = 16 [-]<br />
Bur n i ;3 = 0 Bur n o = 18 [-]<br />
COND1 c;i = 35 COND1 c;o = 36<br />
COND1 r ;i = 51 COND1 r ;o = 52<br />
COND2 c;i = 33 COND2 c;o = 34<br />
COND2 r ;i = 71 COND2 r ;o = 72<br />
COP ABS = 1,412 [-] COP ABS;f uel = 0,4556 [-]<br />
COP ABS;heat = 0,7657 [-] C p M I X L1;o = 1,912 [ k J/kg-K ]<br />
C p pump1;i = 1,978 [ k J/kg-K ] C p pump1;o = 1,978 [ k J/kg-K ]<br />
C p pump2;i = 2,037 [ k J/kg-K ] C p pump2;o = 2,037 [ k J/kg-K ]<br />
C p SHE X 1;hi = 1,912 [ k J/kg-K ] C p SHE X 2;hi = 1,987 [ k J/kg-K ]<br />
∆ h;C HK ;min = 13,63 [ k J/kg ] ∆ Ḣ f uel = 100<br />
∆ Ḣ i = 100 [kW ] ∆ h;M I X L1;chk = 13,63 [ k J/kg ]<br />
∆ h;V B1;chk = 11,61 [ k J/kg ] ∆ h;V B2;chk = 24,12 [ k J/kg ]<br />
∆ p;ABSO;1 = 0 [kPa]<br />
∆ p;ABSO;2 = 0 [kPa]<br />
∆ p;ABSO;c = 0 [kPa]<br />
∆ p;BURN ;i ;1 = −8 [kPa]<br />
∆ p;BURN ;i ;2 = −1 [kPa]<br />
∆ p;COND1;c = 0 [kPa]<br />
∆ p;COND1;r = 0 [kPa]<br />
∆ p;COND2;c = 0 [kPa]<br />
∆ p;COND2;r = 0 [kPa]<br />
∆ p;DES1;h = 0 [kPa]<br />
∆ p;DES1;r = 0 [kPa]<br />
∆ p;DES1;s = 0 [kPa]<br />
∆ p;DES2;h = 2,776 × 10 −17 [kPa] ∆ p;DES2;r = 0 [kPa]<br />
∆ p;DES2;s = 0 [kPa]<br />
∆ p;EV AP;c = 0 [kPa]<br />
∆ p;EV AP;r = 0 [kPa]<br />
∆ p;GGHE X 1;c = −1 [kPa]<br />
∆ p;GGHE X 1;h = −1 [kPa] ∆ p;GGHE X 2;c = −1 [kPa]<br />
∆ p;GGHE X 2;h = −1 [kPa] ∆ p;GGHE X 3;c = −4 [kPa]<br />
∆ p;GGHE X 3;h = −4 [kPa] ∆ p;GGHE X 4;c = −2 [kPa]<br />
∆ p;GGHE X 4;h = −2 [kPa] ∆ p;M I XG1;i ;1 = −0,1 [kPa]<br />
∆ p;M I XG1;i ;2 = 9,1 [kPa] ∆ p;M I XG2;i ;1 = −0,1 [kPa]<br />
∆ p;M I XG2;i ;2 = −1,1 [kPa] ∆ p;M I X L1;1 = 0 [kPa]<br />
∆ p;M I X L1;2 = 0 [kPa]<br />
∆ p;M I X R1;1 = 0 [kPa]<br />
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