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integration of solid oxide fuel cells and ... - Ea Energianalyse

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C. EES<br />

∆p;GGHE X 1;c = −1 ± −1[kPa] ∂ηHW /∂∆p;GGHE X 1;c = −7,258E − 10 0,00 %<br />

∆p;GGHE X 1;h = −1 ± −1[kPa] ∂ηHW /∂∆p;GGHE X 1;h = −4,811E − 14 0,00 %<br />

∆p;GGHE X 2;c = −1 ± −1[kPa] ∂ηHW /∂∆p;GGHE X 2;c = −4,845E − 14 0,00 %<br />

∆p;GGHE X 2;h = −1 ± −1[kPa] ∂ηHW /∂∆p;GGHE X 2;h = 3,862E − 14 0,00 %<br />

∆p;GGHE X 3;c = −4 ± −4[kPa] ∂ηHW /∂∆p;GGHE X 3;c = −0,002301 30,18 %<br />

∆p;GGHE X 3;h = −4 ± −4[kPa] ∂ηHW /∂∆p;GGHE X 3;h = −0,002301 30,18 %<br />

∆p;GGHE X 4;c = −2 ± −2[kPa] ∂ηHW /∂∆p;GGHE X 4;c = −0,002301 7,54 %<br />

∆p;GGHE X 4;h = −2 ± −2[kPa] ∂ηHW /∂∆p;GGHE X 4;h = −0,002301 7,54 %<br />

∆p;M I XG1;i ;1 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;M I XG1;i ;1 = −1,426E − 08 0,00 %<br />

∆p;M I XG2;i ;1 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;M I XG2;i ;1 = −0,002301 0,02 %<br />

∆p;PR = −5 ± −5[kPa] ∂ηHW /∂∆p;PR = −1,475E − 11 0,00 %<br />

∆p;SPG1;o;1 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;SPG1;o;1 = 3,388E − 14 0,00 %<br />

∆p;SPG1;o;2 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;SPG1;o;2 = 8,640E − 13 0,00 %<br />

∆p;SPG2;o;1 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;SPG2;o;1 = −0,002301 0,02 %<br />

∆p;SPG2;o;2 = −0,1 ± −0,1[kPa] ∂ηHW /∂∆p;SPG2;o;2 = −7,361E − 10 0,00 %<br />

∆p;W GHE X 1;g = −2 ± −2[kPa] ∂ηHW /∂∆p;W GHE X 1;g = −0,002301 7,54 %<br />

∆p;W GHE X 2;g = −2 ± −2[kPa] ∂ηHW /∂∆p;W GHE X 2;g = −0,002301 7,54 %<br />

∆p;W GHE X 3;g = −2 ± −2[kPa] ∂ηHW /∂∆p;W GHE X 3;g = −0,002301 7,54 %<br />

ηsys;el ;net = 0,516 ± 0,01676[-]<br />

∆p;BURN ;i ;1 = −8 ± −8[kPa] ∂ηsys;el;net /∂∆p;BURN ;i ;1 = −4,987E − 09 0,00 %<br />

∆p;BURN ;i ;2 = −1 ± −1[kPa] ∂ηsys;el;net /∂∆p;BURN ;i ;2 = 0,002301 1,89 %<br />

∆p;GGHE X 1;c = −1 ± −1[kPa] ∂ηsys;el;net /∂∆p;GGHE X 1;c = −6,200E − 08 0,00 %<br />

∆p;GGHE X 1;h = −1 ± −1[kPa] ∂ηsys;el;net /∂∆p;GGHE X 1;h = −7,212E − 08 0,00 %<br />

∆p;GGHE X 2;c = −1 ± −1[kPa] ∂ηsys;el;net /∂∆p;GGHE X 2;c = −2,729E − 08 0,00 %<br />

∆p;GGHE X 2;h = −1 ± −1[kPa] ∂ηsys;el;net /∂∆p;GGHE X 2;h = −4,800E − 09 0,00 %<br />

∆p;GGHE X 3;c = −4 ± −4[kPa] ∂ηsys;el;net /∂∆p;GGHE X 3;c = 0,002301 30,18 %<br />

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