Technologies and Costs for Removal of Arsenic From Drinking Water

equation y = (2*10 -8 )x 2 + 0.0002x + 0.8394. The integral of this equation was used to estimatethe area under the curve. The integral equation is:z = (2*10 -8 )/3*x 3 + 0.0001x 2 + 0.8394x.For x = 4300 BV:As pass = (2*10 -8 )/3*(4300) 3 + 0.0001*(4300) 2 + 0.8394*4300As pass = 5988 Fg*BV/L.The arsenic adsorbed onto the activated alumina was calculated by subtracting the arsenic thatpassed through the column from the total arsenic in the influent.As ads = As tot - As pass = (4300 BV)(22.8 Fg/L) - 5988 Fg*BV/LAs ads = 98,040 - 5988 Fg*BV/L = 92,052 Fg*BV/LThe arsenic adsorbed onto the activated alumina is often reported in milligrams arsenic pergram of activated alumina. The Phase 3 Report refers to this as As loading in Table 4. In thePhase 3 Report, a bed volume was 0.375 L. To calculate the arsenic loading, the density ofAlcoa CPN is needed. The packed bulk density for Alcoa CPN is 47 lb/ft 3 or 750 kg/m 3 .Arsenic loading is calculated as follows:As loading = [(92,052 Fg*BV/L)(0.375 L/BV)(mg/1000 Fg)](0.375 L)(dm 3 /L)(m 3 /1000 dm 3 )(750 kg/m 3 )(1000 g/kg)As loading = 0.12 mg As/g AA for breakthrough at 2 Fg/LArsenic loading will vary based on the breakthrough concentration. For breakthrough at 10Fg/L, the run length is 16,500 BV. Using the integral equation yields the following:As pass = 71,023 Fg*BV/LAs ads = (22.8 Fg/L)(16,500 BV) - 71,023 Fg*BV/L = 305,177 Fg*BV/LD-15