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Pierre André Chiappori (Columbia) "Family Economics" - Cemmap

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300 7. Matching on the Marriage Market: Theory<br />

Notice that the entries in this matrix are just the sums of the two terms in<br />

Example 7.3 discussed above. In this regard, non transferable utility can<br />

be thought of as a special case of transferable utility, where the division<br />

of the output in each marriage is predetermined and cannot be modified<br />

by transfers between spouses. For instance, if each partner receives half of<br />

the marital output in any potential marriage, the Gale Shapley algorithm<br />

yields the unique stable outcome, which is on the diagonal of this matrix. In<br />

contrast, with transferable utility, the unique assignment that maximizes<br />

aggregate marital output, indicated by the bold numbers in the matrix<br />

below, is not on the diagonal. This assignment yields aggregate output of<br />

16, compared with an aggregate output of 14 on the diagonal.<br />

Men<br />

Women<br />

1 2 3<br />

1 5 8 2<br />

2 7 9 6<br />

3 2 3 0<br />

Though all men would obtain the highest marital output with woman 2,<br />

and all women would obtain the highest output with man 2 (implying that<br />

ζ 22 is the largest entry in the marital output matrix 7.4), the best man<br />

and the best woman are not married to each other. With transfers, the<br />

assignment on the diagonal is no longer stable, because if couple 1, 1 and<br />

couple 2, 2 exchange partners, there is an aggregate gain of 1 unit of the<br />

transferable good. Then man 1 can, despite his lower contribution to the<br />

marital output, bid away the best woman by offering her a larger amount<br />

of private consumption and still be better off than in the initial match with<br />

woman 1. Similarly, woman 1 can bid away the best man by offering him a<br />

larger share of private consumption and still be better off than in the initial<br />

match with man 1. Thehigheraggregate output achievable when man 2<br />

and woman 2 are not married to each other implies that, for any division<br />

of the marital output of 9 that these partners can obtain together, at least<br />

oneofthepartnerscanbemadebetteroff in an alternative marriage.<br />

Stable matching with a finite number of agents<br />

Let us now consider the general assignment problem with M males and N<br />

females. Let ζ ij denote the total output of a marriage between male i and<br />

female j, andletζ i0 (resp. ζ 0j) be the utility that person i (resp. person<br />

j) receives as single (with ζ 00 =0by notational convention). Then the<br />

difference zij = ζ ij − ζ i0 − ζ 0j is the marital surplus that male i and female<br />

j generate by marrying each other.<br />

We define assignment indicators, aij, suchthataij =1if and only if<br />

i is married with j and aij =0otherwise. We also define ai0 =1if and<br />

only if i is single, and similarly a0j =1if and only if j is single. Then,<br />

following Gale (1960, chapters 1 and 5) and Shapley and Shubik (1972),

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