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Pierre André Chiappori (Columbia) "Family Economics" - Cemmap

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is by increasing s. Specifically,<br />

11. Marriage, Divorce, Children 471<br />

∂a(s, yh)<br />

= λ(u<br />

∂s<br />

0 m(s) − γ<br />

) ≥ 0, (11.19)<br />

wm<br />

∂a(s, yh)<br />

= 1−λ(1 + α) > 1,<br />

∂yh<br />

∂q(s, yh)<br />

= u<br />

∂s<br />

0 ∂a(s, yh)<br />

m(s) − > 0,<br />

∂s<br />

∂q(s, yh) ∂a(s, yh)<br />

= − ≤ 0.<br />

∂yh<br />

∂yh<br />

An increase in the transfer s raises the utility that the mother would receive<br />

as single and improves her bargaining position in the newly formed<br />

household. Consequently, the remarried mother works less and spends more<br />

time with the child, which raises the utility of the child. 12 However, an<br />

increase in s also has the unintended effect of raising the new husband’s<br />

utility, who "eats" part of the transfer. An increase in the net income of the<br />

new husband raises his gain from marriage a(s, yh)−yh because the mother<br />

spends less time with the child and more time in the market. The mother<br />

is willing to do such a sacrifice of child quality because she is compensated<br />

by a higher level of adult consumption, jointly with the new husband.<br />

The result that remarried mothers work more in the market may seem<br />

counterfactual. 13 We emphasize that market work is just one way of transferring<br />

resources from the child to the new husband and the crucial assumption<br />

is the availability of a linear transfer in some non-trivial range.<br />

For instance, the mother may spend less time with the child and more time<br />

with the new husband in joint leisure activities. As long as such substitutions<br />

are available at a fixed rate of exchange, the results are the same as<br />

if the remarried mother would spend time working in the market.<br />

11.4 Transfers, the interim perspective<br />

Following separation, the parents can be in four different states, depending<br />

on the new marital status of their ex spouses:<br />

1. Both parents are single, which happens with probability (1 − p) 2 .<br />

12 ∂a(s,y<br />

Note that h)<br />

=0if s =ĉ, ∂s<br />

∂a(s,yh) =1if s = c ∂s<br />

∗ and 1 > ∂a(s,yh) > 0 for<br />

∂s<br />

ĉ

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