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Q2 Z2,(Q2) Z2(Q2) - Institute for Water Resources - U.S. Army

Q2 Z2,(Q2) Z2(Q2) - Institute for Water Resources - U.S. Army

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To dotermine the distance traveled during an acceleration from<br />

v = 0 to v = plq, the definite integral of Equation (3.25) from<br />

t 0 to t = T a is obtained, i.e., where. D a is acceleration distance,<br />

r a<br />

v dt = .L D = In<br />

a k<br />

0<br />

2<br />

R i - R 9 R 1 Ta<br />

KT I 2k 2<br />

a<br />

e KTa - R<br />

2<br />

I<br />

2<br />

(3.27)<br />

No general solution, such as Equation (3.24), exists in the case<br />

of the equation of.motion applicable to rail trains, Equation (3.21) .. -<br />

distance <strong>for</strong> vehicles possessing such an equation of motion. These<br />

will be presented in Chapter V in the discussion of the rail process<br />

function.<br />

Deceleration State. Deceleration is a good deal more complicated<br />

than is acceleration because (1) it may consist of coasting and brak-<br />

ing stages and (2) additional resistance <strong>for</strong>ces, e.g., engine drag,<br />

may occur. That is, if the motive <strong>for</strong>ce ceases, the vehicle will<br />

coast to a stop. One can hasten the process by adding drag <strong>for</strong>ces<br />

such as braking or reversing engines. One mist make assumptions about<br />

how much drag <strong>for</strong>ces are increased; and, apparently, engineering prac-<br />

tice is to assume coasting and braking at constant rates. 12 Then the<br />

time, T c , required to coast from one constant velocity, V, to another,<br />

V c , at a constant rate c is<br />

T c = (V - V)/c. 13 (3.28)<br />

There are, however, various ways to estimate the acceleration time and<br />

57

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