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A. Sistem Pertidaksamaan Linear

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. Untuk barisan –8, –4, –2, –1, ....<br />

r = 4 − −2<br />

=<br />

− 8 − 4<br />

−1<br />

=<br />

− 2<br />

= 1<br />

2<br />

c. Untuk barisan 1, 2, 2 2 , 2 3 , ....<br />

r = 2<br />

1 =<br />

2<br />

2<br />

2 =<br />

3<br />

2<br />

2 = 2<br />

2<br />

Ketiga barisan tersebut dinamakan barisan geometri.<br />

a. Suku ke–n Barisan Geometri<br />

Misalkan diketahui suatu barisan geometri U , U , U , ..., U 1 2 3 n<br />

dengan rasio r dan U = a, maka:<br />

1<br />

U = a = ar 1 0 1 – 1 = ar<br />

U = ar = ar 2 1 2 – 1 = ar<br />

U = ar 3 2 = ar2 3 – 1 = ar<br />

...<br />

n – 1 U = ar n<br />

Sehingga suku ke–n barisan geometri adalah:<br />

U n = ar n – 1 dengan r =<br />

Un<br />

U −<br />

n 1<br />

Contoh 3.12<br />

Tentukan suku pertama, rasio, dan suku ketujuh pada barisan–barisan<br />

geometri berikut:<br />

1) 1, –2, 4, –8, ....<br />

2) 200, 100, 50, 25, ....<br />

Jawab:<br />

1) 1, –2, 4, –8, ...<br />

a = 1, r = 2 −<br />

= –2<br />

1<br />

U = ar 7 6 = 1(–2) 6 = 64<br />

2) 200, 100, 50, 25, ....<br />

a = 200, r = 100<br />

200<br />

6<br />

= 1<br />

2<br />

U = ar 7 6 ⎛ 1 ⎞ 25<br />

= 200 ⎜ ⎟ =<br />

⎝2⎠ 8<br />

Contoh 3.13<br />

Dalam suatu barisan geometri diketahui U = 27 dan U = 1. Tentukan<br />

1 4<br />

4 suku pertama barisan geometri tersebut!<br />

Barisan dan Deret 95

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