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STANDARD HANDBOOK OF PETROLEUM & NATURAL GAS ...

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where DF =<br />

W=<br />

Wd‘ =<br />

%=<br />

K, =<br />

r, =<br />

r,, =<br />

Drill String: Composition and Design 721<br />

design factor (DF = 1.1-1.2)<br />

weight on bit in lb<br />

unit weight of drill collar in air in lb/ft<br />

buoyancy factor<br />

1 - Ym/Ysc<br />

drilling fluid density, e.g., in lb/gal<br />

drill collar density, e.g., in Ib/gal (for steel, y, = 65.5 lb/gal)<br />

a= hole inclination from vertical in degrees (”)<br />

Design factor (DF) is needed to place the neutral point below the top of the<br />

drill collar string. Some excess of drill collar weight is required to take care of<br />

inaccurate handling of the brake by the driller. For an “ideal driller,” the design<br />

factor should be equal to 1. The excess of drill collars also helps to prevent<br />

transverse movement of drill pipe due to the effect of centrifugal force. While<br />

the drill string rotates, a centrifugal force is generated that may produce a lateral<br />

movement of drill pipe and, in turn, bending stress and excessive torque. The<br />

centrifugal force also contributes to vibration of the drill pie. Hence, some<br />

excess of drill collars is suggested. The magnitude of the design factor can be<br />

determined by field experiments in any particular set of drilling conditions.<br />

The pressure area method (PAM), occasionally used for evaluation of drill<br />

collar string length, is wrong because it does not consider the triaxial state of<br />

stresses that actually occurs. It must be remembered that hydrostatic forces<br />

cannot cause any buckling of the drill string as long as the density of the string<br />

is greater than the density of the drilling fluid.<br />

Example<br />

Determine the required length of 7 by 2t-in. drill collars if desired weight<br />

on bit is W = 40,000 lb, drilling fluid density y, = 100 lb/gal, and hole deviation<br />

from vertical a = 20”. From offset wells, it is known that a design factor DF of<br />

1.1 is satisfactory.<br />

Solution<br />

From Table 4-75 the unit weight of drill collar WdC = 117 lb/ft. The buoyant<br />

factor is<br />

10<br />

K, = 1 - - = 0.847<br />

65.5<br />

Applying Equation 4-50 gives<br />

(1‘1)(40,000) = 376ft<br />

L,, =<br />

(147)(0.847)(cos20)<br />

The closed length, based on 30-ft collars, is 390 ft or 13 joints of drill collars.<br />

Actually, drill collar sizes and lengths should be considered simultaneously.<br />

The optimal selection should result in the maximum penetration rate. Such an<br />

approach, however complex, is particularly important when drilling formations<br />

sensitive to the effect of differential pressure and also in cases where the amount<br />

of hydraulic energy delivered at the rock bit is a controlling factor of drilling<br />

efficiency.

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