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STANDARD HANDBOOK OF PETROLEUM & NATURAL GAS ...

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Drilling Mud Hydraulics 835<br />

words, the total pressure drop between two points of a flow conduit is the sum<br />

of the components mentioned above. Thus,<br />

AP = AP) + AP4 + AP, (4- 104)<br />

where APF = frictional pressure drop<br />

APa = accelerational pressure drop<br />

AP, = gravitational pressure drop (hydrostatic head)<br />

Equation 4-104 expresses the principle of additive pressures. In addition to<br />

Equation 4-104, there is the equation of state for the drilling fluid.<br />

Typically, water based muds are considered to be incompressible or slightly<br />

compressible. For the flow in drill pipe or drill collars, the acceleration<br />

component (AP,) of the total pressure drop is negligible, and Equation 4-104<br />

can be reduced to<br />

AP = APk + APc, (4-1 05)<br />

Equations 4-102 through 4-105 are valid in any consistent system of units.<br />

Example<br />

The following data are given:<br />

Pressure drop inside the drill string = 600 psi<br />

Pressure drop in annular space = 200 psi<br />

Pressure drop through the bit nozzle = 600 psi<br />

Hole depth = 10,000 ft<br />

Mud density = 10 lb/gal<br />

Calculate<br />

bottomhole pressure<br />

pressure inside the string at the bit level (above the nozzles)<br />

drill pipe pressure<br />

Because the fluid flow in annular space is upward, the total bottom hole<br />

pressure is equal to the hydrostatic head plus the pressure loss in the annulus.<br />

Bottom hole pressure Photlom (psi),<br />

Ph

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