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STANDARD HANDBOOK OF PETROLEUM & NATURAL GAS ...

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928 Drilling and Well Completions<br />

housing stops abruptly. Compute the maximum deceleration x in g's<br />

and the deceleration time t. All calculations can be made in English or<br />

metric units.<br />

2. Taking into account the spring only compute the distance traveled x and<br />

the maximum deceleration a in g's when the housing stops abruptly.<br />

3. Now if both the spring and the shock absorber are acting together, what<br />

will be the distance traveled x and the maximum deceleration a in g's when<br />

the housing stops abruptly?<br />

4. What is the advantage in adding a shock absorber to the spring in such a<br />

system?<br />

Solution<br />

1. Neglect the effect of gravity. Energy balance: Fx = 4 mv2 (v = 3.048 m/s)<br />

x = mv2/2F = 0.209 m<br />

a = F/m = 22.24 m/s2 = 2.26 g<br />

x = +at2 + t = (2~/a)'/~ = 0.137 s<br />

x = 0.209 m = 0.685 ft = 8.23 in. = 20.9 cm<br />

a = 2.26 g<br />

t = 0.137 s = 137 ms<br />

2. Before the tool hits, going down at a constant velocity, the spring is already<br />

compressed by the weight of the instrument package, so the effect of<br />

gravity can be neglected. Energy balance:<br />

;Smv2 = +kx2<br />

x = (mv2/k)'/' = 0.043 m = 0.141 ft = 1.69 in.<br />

Fma = kx = 430 N<br />

a = F/m = 215 m/s2 = 705.38 ft/s2 = 21.9 g<br />

x = 0.043 m = 0.141 ft = 4.3 cm = 1.69 in.<br />

a = 21.9 g<br />

3. Still neglecting gravity. Energy balance: Fx + +kx2 = +mv2<br />

kx2 + 2Fx - mv2 = 0<br />

x = [-F + (F2 + kmv2)1/21/k = 0.0388 m = 0.127 ft = 1.53 in. = 3.88 cm<br />

F, = FS + 1/2 kx = 432.5 N<br />

a = F/m = 216.2 m/s2 = 709.5 ft/s2 = 22.03 g<br />

x = 3.88 cm = 1.53 in.<br />

a = 22.03 g<br />

4. Oscillations will be dampened; x slightly decreased: 3.88 cm versus 4.3 cm.<br />

Teledrift and Teleorienter<br />

The first transmission of data during drilling using mud pulses was commercialized<br />

by B.J. Hughes Inc. in 1965 under the name of teledrift and<br />

teleorienter. Both tools are purely mechanical. A general sketch of principle is<br />

given in Figure 4-239. The tool is now operated by Teledrift Inc.<br />

The tool generates at bottom positive pulses by restricting momentarily the<br />

flow of mud each time that the mud flow (pumps) is started. The pulses are<br />

detected at surface on the stand pipe and recorded as a function of time.<br />

Figure 4-240 shows the sketch of principle of the teledrift unit which is<br />

measuring inclination.<br />

A pendulum hangs in a conical grooved bore. A spring tends to move the<br />

pendulum and the poppet valve upwards when the circulation stops. If the tool

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