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STANDARD HANDBOOK OF PETROLEUM & NATURAL GAS ...

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Drill String: Composition and Design 747<br />

(4-63)<br />

where Pc = minimum collapse pressure resistance as specified by API in psi<br />

PCc = corrected collapse pressure resistance for effect of tension in psi<br />

Ym = minimal yield strength of pipe in psi<br />

Substituting Equation 4-63 and Equation 455 into Equation 4-54 (note: or = 0,<br />

z = 0, oe = Y,) and solving PCc yields<br />

(4-64)<br />

or<br />

P,, =<br />

(4-65)<br />

Equation 4-65 indicates that increased tensile load results in decreased collapse<br />

pressure resistance. The decrement of collapse pressure resistance during normal<br />

DST operations is relatively small; nevertheless, under certain conditions, it may<br />

be quite considerable.<br />

Example<br />

Determine if the drill pipe is strong enough to satisfy the safety factor on<br />

collapse of 1.1 for the DST conditions as below:<br />

Drill pipe: 4+-in., 16.6-lb/ft nominal weight, G-105 steel grade, class 2<br />

Drilling fluid with a density of 12 lb/gal and drill pipe empty inside<br />

Packer set at the depth of 8,500 ft<br />

Tension load of 45,000 lb, applied to the drill pipe<br />

From Table 4-84, the collapse pressure resistance in uniaxial state of stress,<br />

Pc - 6,010 psi. Reduced wall thickness for class 2 drill pipe = (0.65)(0.337) =<br />

0.219 in. Reduced Ddp for class 2 drill pipe = 3.826 + (2)(0.219) = 4.264 in.<br />

Reduced cross-sectional area of class 2 drill pipe equals:<br />

IC<br />

IC<br />

-(4.264)'--(3.826)'<br />

4 4<br />

= 2.783in.'<br />

The axial tensile stress at packer level is<br />

o z = L = 45 Oo0 16,170psi<br />

2.783

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