Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
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,,_Td d a a c c b b<br />
DISTANCE<br />
Figure 10-6. Two inversions <strong>and</strong> one interchange.<br />
--',"<br />
NOTRANSPOSITIONS.<br />
I<br />
I<br />
t<br />
I<br />
the two IF b<strong>and</strong>s without inversion as shown in Figure<br />
10.6. Let<br />
1.; +A 1"3+[4<br />
7=1 - 1<br />
21.o 21.o<br />
be the fractional frequency interval from the pilot to the<br />
center <strong>of</strong> each IF b<strong>and</strong>, <strong>and</strong> let e = lSI -'h'l be the<br />
fractional departure <strong>of</strong> any IF frequency from its b<strong>and</strong><br />
center. Then, for the transmission system depicted in<br />
Figure 10-6, a frequency introduced as1.=1.o (I + 3, + e)<br />
will be sent one quarter <strong>of</strong> the distance, converted to<br />
1"o (1 - 3, - e), sent one quarter <strong>of</strong> the distance, converted<br />
to [o (1 + 3, - e), sent one quarter <strong>of</strong> the distance,<br />
converted to 1.o (1 - 3, + e), <strong>and</strong> sent the remaining<br />
quarter <strong>of</strong> the distance. The total relative normalized<br />
loss is therefore<br />
1<br />
P =4 [_/1 +(7+e) + _/1 -(.T+e) + _/1 +('T-e)<br />
+ x/J - (.T- e) 1 - 1 (8)<br />
/ \<br />
3'2 5")'4 e 2 [ 15 ._ 5e 4<br />
8 128 8 8 128<br />
+...---_+--8;- --+..<br />
(8a)<br />
Because 3, is constant, only the latter terms in e 2 <strong>and</strong> e 4<br />
involve variation in transmission across the b<strong>and</strong>. Since<br />
only even powers occur, each b<strong>and</strong> is symmetrical about<br />
the center, This is to be expected since in Figure 10-6,<br />
for example, one observes that each b<strong>and</strong> edge successively<br />
occupies all four frequencies/l, J'2, f3, I4.<br />
By analogy to the transposition <strong>of</strong> open-wire lines to<br />
avoid crosstalk, we shall refer to this method <strong>of</strong><br />
obtaining uniform response as transposition equalization.<br />
Figure 10-7 shows the relative normalized loss with<br />
no transposition, with one midpoint inversion <strong>and</strong> with<br />
two inversions <strong>and</strong> a b<strong>and</strong> interchange. If ao = 120 dB,<br />
i<br />
I<br />
_2889<br />
A • GNE INVERSION<br />
B = TWO INVERSIONS AND<br />
ONE<br />
L<br />
INTERCHANGE<br />
0 I O0 200 300 400 500<br />
Figure 10-7. Effect o1. transposition equalization.<br />
we see that with one inversion (,4 curves) both IF b<strong>and</strong>s<br />
have a slope <strong>of</strong> 120 (-0.0116 + 0.0742) = 7.5 dB from<br />
the inner to the outer edges. Over a 20 ° C range, this<br />
slope would vary by (10/293) 7.5 _ 0.34 dB, which is<br />
probably small enough not to require compensation.<br />
Also, the equalizers to correct the slope across the b<strong>and</strong><br />
present no serious problem. However, a large level<br />
difference between IF b<strong>and</strong>s will accumulate (on the<br />
longer lines) before the single inversion at the midpoint.<br />
On the longer lines, three (or five) inversions might be<br />
necessary.<br />
If a midpoint b<strong>and</strong> interchange is used, together with<br />
an inversion at the one-quarter <strong>and</strong> three-quarter points,<br />
we see from the B curves that the transmission in each<br />
IF b<strong>and</strong> is symmetrical about the b<strong>and</strong> center <strong>and</strong> is<br />
120(-O.0341 + 0.0429) _ 1 dB greater at the b<strong>and</strong><br />
edges than at the centers. No temperature compensation<br />
is needed <strong>and</strong> the normal roll<strong>of</strong>fs <strong>of</strong> the IF amplifiers<br />
<strong>and</strong> filters can be used to flatten the passb<strong>and</strong> to within<br />
a tenth <strong>of</strong> a decibel if desired.<br />
If the pilot frequency,fo, lies midway between the two<br />
b<strong>and</strong>s-that is, if/o = (]'2 + f3)/2 = (fl +[4)/2, <strong>and</strong> if<br />
1.3 - f2 = 21.1 -the inversions <strong>and</strong> interchanges are easily<br />
accomplished. (We are assuming that (f2 -fl ) = (/4 -1"3),<br />
L<br />
112