Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
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<strong>and</strong>is the (discrete) two-dimensional Fourier transform<br />
<strong>of</strong> A(x i_vj). Because y is constant during the summation<br />
over i (or, alternatively, x is constant during the<br />
summation over /), equation (47) can be written as a<br />
two-step<br />
process<br />
e<br />
-ikuxi<br />
a(u,v) = _ -ikvy] _. A(xi'Yi)e (48)<br />
Radiative<br />
Imaging<br />
1 t<br />
One obvious way to implement equation (47) is to<br />
radiate the IF signals from the signal plane <strong>and</strong> to receive<br />
this radiation in the image plane, in exact analogy to the<br />
optical spectrum analyzer. The waves radiated may be<br />
acoustic, as suggested by Oliver (ref. 11) <strong>and</strong> McLean<br />
<strong>and</strong> Wild (ref. 12), or electromagnetic. If the signal <strong>and</strong><br />
image planes are separated a distance _, several alternatives<br />
exist for bringing the waves to focus in the image<br />
plane:<br />
1. We may interpose a lens <strong>of</strong> focal length _/2<br />
midway between the planes.<br />
2. We may interpose two lenses one <strong>of</strong> focal length<br />
(the focussing lens) in front <strong>of</strong> the signal plane <strong>and</strong><br />
the other <strong>of</strong> focal length _/2 (the field flattene0 in<br />
front <strong>of</strong> the image plane.<br />
3. We may curve the signal <strong>and</strong> image planes into<br />
appropriate spherical surfaces.<br />
4. We may delay the signals to the central elements<br />
so as to radiate a spherical wavefront from a plane<br />
array.<br />
With any <strong>of</strong> these alternatives, the phase shift produced<br />
by the propagation delay between points on the two<br />
surfaces will be a constant (-2rr_/?_ i for alternative 3)<br />
plus a term<br />
27r<br />
¢i = - _ (ux' + vy')<br />
_i<br />
2fro<br />
= - _ (ux + vy) (49)<br />
where _'i is the wavelength <strong>of</strong> the radiation used.<br />
Comparing equations (49) with (38) we see that<br />
2ff(l<br />
- (50)<br />
so that the effective focal length equation (50) can now<br />
be written<br />
frXfl hi _ frv<br />
F ......... (51)<br />
oc _r o rico<br />
where v is the velocity <strong>of</strong> propagation <strong>of</strong> the waves used.<br />
We now wish to point out a fundamental limitation<br />
<strong>of</strong> all radiative imaging processes. If fi is obtained by<br />
heterodyning fr, then fi = fr - fo where fo is a constant<br />
frequency. Then equation (51) becomes<br />
F = (52)<br />
teA-re<br />
As fr varies from one end <strong>of</strong> the IF b<strong>and</strong> to the other,<br />
the fractional variation in fr-re is greater <strong>and</strong> the<br />
effective focal length F changes with frequency• Low IF<br />
frequencies are imaged with more magnification than<br />
high IF frequencies. Thus, a wide-b<strong>and</strong> source will be<br />
imaged not as a point but as a radial line whose intensity<br />
pr<strong>of</strong>'fle is the power spectrum (versus wavelength)<strong>of</strong> the<br />
source. This may have its uses, but it does not produce<br />
good images• By analogy with a similar defect in lenses,<br />
we shall call this phenomenon lateral chromatic aberration.<br />
There appears to be no way to avoid lateral<br />
chromatic aberration other than to make .to zero. This<br />
means doing the radiative imaging at the original RF<br />
frequency.<br />
We then have yet another problem: Unless adequate<br />
shielding is provided, the electrical signals generated for<br />
imaging could be picked up by the antennas, thereby<br />
producing serious feedback. Unless we are careful we<br />
might end up with the world's most expensive oscillator.<br />
Because the antennas need not be aimed at the imager<br />
<strong>and</strong> because the array is completely dephased for any<br />
nearby signal, we are really concerned only with the far<br />
out side lobe response <strong>of</strong> the nearest elements. Hopefully,<br />
this can be 20 dB or more below that <strong>of</strong> an<br />
isotropic antenna. Nevertheless, careful shielding is<br />
essential.<br />
If we are forced by the feedback problem to use a<br />
frequency <strong>of</strong>fset, some chromatic aberration will remain.<br />
To be effective in suppressing feedback, fo must be at<br />
least equal to the system b<strong>and</strong>width B. lff c is the center<br />
frequency <strong>of</strong> the RF b<strong>and</strong> <strong>and</strong> .to = -B (that is, we<br />
actually use an upward <strong>of</strong>fset), <strong>and</strong> if we let x = Bffo<br />
then from equation (52) the fractional change in F is<br />
144