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Project Cyclops, A Design... - Department of Earth and Planetary ...

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x/eeoG + Ueo2<br />

o =<br />

(D42)<br />

while that approached by the noise alone will be<br />

centered at P ---Po <strong>and</strong> will have the variance<br />

O"O -<br />

x/- q-o<br />

x/if-<br />

(D43)<br />

where /a = 1 if n discrete independent samples are<br />

averaged <strong>and</strong> /a = 2/3 if sin x/x filters are used with<br />

n = r/T. See eqs. (DI8) <strong>and</strong> (D29).<br />

The threshold must exceed the mean, Po, <strong>of</strong> the noise<br />

distribution by some multiple mo times Oo where mo is<br />

chosen to give the desired Pfa' <strong>and</strong> is determined by<br />

circuits following the photocell <strong>and</strong> simply count the<br />

number <strong>of</strong> photons received. The statistical distribution<br />

<strong>of</strong> this count will depend on the signal <strong>and</strong> background<br />

signal strengths <strong>and</strong> on the number <strong>of</strong> Nvcluist intervals<br />

over which the count is taken-that is, on the value <strong>of</strong><br />

n = (Br) where B is the b<strong>and</strong>width <strong>of</strong> the (ideal) optical<br />

filter ahead <strong>of</strong> the photodetector <strong>and</strong> z is the integration<br />

time.<br />

Incoherent Radiation: Short Integration Time<br />

If the integration time is short compared with lIB,<br />

the probability p(n) <strong>of</strong> receiving n photons is the<br />

exponential<br />

distribution<br />

,<br />

p(n) - I +no ITTn-/o/<br />

(o48)<br />

Pfa = e-Z2 leclz (D44)<br />

The mean, Po + Pr, <strong>of</strong> the distribution with signal<br />

present must be some multiple m times o above the<br />

threshold, where rn is chosen to give the allowable<br />

probability <strong>of</strong> missing the signal, <strong>and</strong> is determined by<br />

where _o = expectation count. The first moment <strong>of</strong> this<br />

distribution is M, = _o, while the second moment is<br />

M2 = _o (1 + 2fro). The mean square fluctuation in<br />

count is therefore<br />

002 = M2 -Mr 2 = no(l +no) (D49)<br />

Prns = e -z2 /2dz (D45)<br />

The limit <strong>of</strong> satisfactory operation is thus given by<br />

If the count _ = fib + ns, where _b is a background<br />

count <strong>and</strong> ns is the count due to the received radiation,<br />

the signal-to-noise power ratio is "_s2/O2. Letting<br />

-fro = r_(Po/hv) r, _s = rl(Ps/hu) r, we find from equation<br />

(D49) that<br />

Pr = mo°o +too = m o _+m<br />

S _S 2 lOS 2<br />

- = (DS0)<br />

N _o(1 +_o) (hv/OPor+Po 2<br />

or:<br />

Pr (mS +vC_mo)+m4m2 + 2X/'-_mo +#n<br />

which is exactly the result we would expect from (D9)<br />

with<br />

Po<br />

n<br />

(D46)<br />

G(f) = [sin lrr/)/(rrr/)l 2<br />

IfPfa = Pros' then mo = m <strong>and</strong><br />

Pr - 2

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