Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
Project Cyclops, A Design... - Department of Earth and Planetary ...
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x/eeoG + Ueo2<br />
o =<br />
(D42)<br />
while that approached by the noise alone will be<br />
centered at P ---Po <strong>and</strong> will have the variance<br />
O"O -<br />
x/- q-o<br />
x/if-<br />
(D43)<br />
where /a = 1 if n discrete independent samples are<br />
averaged <strong>and</strong> /a = 2/3 if sin x/x filters are used with<br />
n = r/T. See eqs. (DI8) <strong>and</strong> (D29).<br />
The threshold must exceed the mean, Po, <strong>of</strong> the noise<br />
distribution by some multiple mo times Oo where mo is<br />
chosen to give the desired Pfa' <strong>and</strong> is determined by<br />
circuits following the photocell <strong>and</strong> simply count the<br />
number <strong>of</strong> photons received. The statistical distribution<br />
<strong>of</strong> this count will depend on the signal <strong>and</strong> background<br />
signal strengths <strong>and</strong> on the number <strong>of</strong> Nvcluist intervals<br />
over which the count is taken-that is, on the value <strong>of</strong><br />
n = (Br) where B is the b<strong>and</strong>width <strong>of</strong> the (ideal) optical<br />
filter ahead <strong>of</strong> the photodetector <strong>and</strong> z is the integration<br />
time.<br />
Incoherent Radiation: Short Integration Time<br />
If the integration time is short compared with lIB,<br />
the probability p(n) <strong>of</strong> receiving n photons is the<br />
exponential<br />
distribution<br />
,<br />
p(n) - I +no ITTn-/o/<br />
(o48)<br />
Pfa = e-Z2 leclz (D44)<br />
The mean, Po + Pr, <strong>of</strong> the distribution with signal<br />
present must be some multiple m times o above the<br />
threshold, where rn is chosen to give the allowable<br />
probability <strong>of</strong> missing the signal, <strong>and</strong> is determined by<br />
where _o = expectation count. The first moment <strong>of</strong> this<br />
distribution is M, = _o, while the second moment is<br />
M2 = _o (1 + 2fro). The mean square fluctuation in<br />
count is therefore<br />
002 = M2 -Mr 2 = no(l +no) (D49)<br />
Prns = e -z2 /2dz (D45)<br />
The limit <strong>of</strong> satisfactory operation is thus given by<br />
If the count _ = fib + ns, where _b is a background<br />
count <strong>and</strong> ns is the count due to the received radiation,<br />
the signal-to-noise power ratio is "_s2/O2. Letting<br />
-fro = r_(Po/hv) r, _s = rl(Ps/hu) r, we find from equation<br />
(D49) that<br />
Pr = mo°o +too = m o _+m<br />
S _S 2 lOS 2<br />
- = (DS0)<br />
N _o(1 +_o) (hv/OPor+Po 2<br />
or:<br />
Pr (mS +vC_mo)+m4m2 + 2X/'-_mo +#n<br />
which is exactly the result we would expect from (D9)<br />
with<br />
Po<br />
n<br />
(D46)<br />
G(f) = [sin lrr/)/(rrr/)l 2<br />
IfPfa = Pros' then mo = m <strong>and</strong><br />
Pr - 2