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Project Cyclops, A Design... - Department of Earth and Planetary ...

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APPENDIX<br />

L<br />

TUNNEL AND CABLE LENGTHS<br />

Exactly n-I lines are needed to connect n points, so<br />

n-I tunnels between adjacent antennas suffice to connect<br />

an array <strong>of</strong> n antennas. One more tunnel is then<br />

needed to tie the array to the central control headquarters.<br />

However, certain main tunnels may be larger<br />

than the branch tunnels <strong>and</strong>, depending on the array<br />

configuration, not all tunnels may be <strong>of</strong> the same length,<br />

so some analysis <strong>of</strong> this problem is in order.<br />

To minimize the tunnel <strong>and</strong> cable lengths required,<br />

the array should be made as compact as possible <strong>and</strong> the<br />

control <strong>and</strong> processing center should indeed be at the<br />

physical center <strong>of</strong> the array. Also the outline <strong>of</strong> the<br />

array should be circular, although small departures from<br />

circularity cause only a second-order change in the total<br />

tunnel <strong>and</strong> cable length. Two obvious configurations<br />

come under consideration: a square lattice in which the<br />

antennas are placed in equally placed rows <strong>and</strong> columns,<br />

<strong>and</strong> a hexagonal lattice in which the antennas are at the<br />

centers <strong>of</strong> the cells <strong>of</strong> a honeycomb. These configurations<br />

correspond to tessellating the array area with<br />

squares <strong>and</strong> hexagons, respectively.<br />

The ratio <strong>of</strong> the area <strong>of</strong> a circle to the area <strong>of</strong> a<br />

circumscribed square is 1r/4 while that <strong>of</strong> a circle <strong>and</strong> the<br />

circumscribed hexagon is 7r/2x/_. However, the spacing s<br />

between antennas must be greater than their diameter d<br />

to prevent shadowing <strong>of</strong> the antennas by their neighbors<br />

.at low elevation angles. If e is the minimum elevation<br />

angle <strong>and</strong> 0m = 0r/2) -e is the maximum angle form the<br />

zenith for unobstructed reception then<br />

d d<br />

s - - (L1)<br />

cos 0m sin e<br />

The filling factor for a square lattice array is therefore<br />

= = - sin 2e (L2)<br />

fs 4 4<br />

while that for a hexagonal array is<br />

lh=2v " = sin e (L3)<br />

Equations (L2) <strong>and</strong> (L3) apply to circular dishes: If<br />

elliptical dishes are used, only the vertical dimension<br />

(minor axis) must be reduced to d = s sin e; the<br />

horizontal dimension (major axis) need be only slightly<br />

less than s. Thus, for elliptical dishes the filling factors<br />

involve sin e rather than sin2e. Table L-1 shows the<br />

realizable filling factors without obstruction.<br />

TABLE<br />

L-I<br />

Circular<br />

Elliptical<br />

e 0m s/d fs fh fs fh<br />

45 ° 45 ° 1.1414 .393 .453 .455 .641<br />

30° 60° 2.000 .196 .227 .393 .453<br />

20 ° 70 ° 2.924 .092 .106 .269 .310<br />

10° 80 ° 5.760 .024 .027 .I 36 .I 57<br />

The filling factor for a hexagonal lattice array is always<br />

2/V_ = 1.155 times as great as for a square lattice array.<br />

If we wish unobstructed operation down to a 20 °<br />

elevation angle, the array diameter must be roughly<br />

three times as great with circular dishes, or x/_ times as<br />

great with elliptical dishes, as would be required for<br />

zenith operation only. Clearly, the use <strong>of</strong> elliptical dishes<br />

would permit significant reduction in the array size <strong>and</strong><br />

215

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