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Project Cyclops, A Design... - Department of Earth and Planetary ...

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APPENDIX<br />

I<br />

CASSEGRAINIAN<br />

GEOMETRY<br />

Consider the paraboloidal primary mirror with its<br />

vertex at V <strong>and</strong> its focus at F as shown in Figure I-1. The<br />

equation <strong>of</strong> its surface is<br />

2/ f<br />

r - - (I1)<br />

1 + cos 0 ) cos 2(01/2)<br />

where f is the focal length FV. The diameter <strong>of</strong> the<br />

paraboloid included by the cone <strong>of</strong> rays <strong>of</strong> half-angle 0<br />

is d = 2r sin 01, so<br />

d sin01 01<br />

--- - tan- (I2)<br />

4f 1 + cos01 2<br />

If an isotropic radiator radiating I W/sr is placed at F,<br />

the flux reflected <strong>of</strong>f the parabola will be:<br />

V ....<br />

\\<br />

\ \<br />

\ \<br />

J<br />

_J..1___--lez_ __ _.<br />

! I v'L i vl'<br />

/<br />

/<br />

/<br />

/<br />

/<br />

/<br />

/<br />

/<br />

/<br />

rl<br />

-\<br />

\<br />

\<br />

\<br />

r2 f2 f2 c°s2 2 (13)<br />

Now assume that a hyperbolic secondary mirror is<br />

introduced with its vertex at V1. Received energy will<br />

now be broughl to focus at F'. If we let 1he distance<br />

OV = OV' = a, then OF = OF' = ea where e is the<br />

eccentricity <strong>of</strong> the hyperboloid. Thus the focal distancc<br />

FI:_ = f) = (e - l)a <strong>and</strong> the focal distance<br />

F'V_ = J'2 = (e + 1)a. The magnification is<br />

f2 e+l<br />

m - - 04)<br />

f_ e- 1<br />

or, conversely,<br />

Figure I-1. A Cassegrainian telescope.<br />

m- I<br />

(15')<br />

209

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