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Feynman Path Integral Formulation

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4.14 Lattice Hamiltonian for Quantum Gravity 139<br />

It is important to note that the squared edge lengths take on only positive values<br />

li 2 > 0, a fact that would seem to imply that the wavefunction has to vanish when<br />

the edge lengths do, Ψ(l 2 = 0) ≃ 0. In addition one has some rather complicated<br />

constraints on the squared edge lengths, due to the triangle inequalities. These ensure<br />

that the areas of triangles and the volumes of tetrahedra are always positive. As<br />

a result one would expect an average soft local upper bound on the squared edge<br />

lengths of the type li<br />

2 < ∼ l2 0 where l 0 is an average edge length, 〈li 2〉 = l2 0 .Theterm<br />

“soft” refers to the fact that while large values for the edge lengths are possible,<br />

these should nevertheless enter with a relatively small probability, due to the small<br />

phase space available in this region.<br />

These considerations have some consequences already in the strong coupling<br />

limit of the theory. For sufficiently strong coupling (large Newton constant G) the<br />

first term in Eq. (4.175) is dominant, which shows again some similarity with what<br />

one finds for non-abelian gauge theories for large g, Eq. (4.157). It is then easy to<br />

see, both from the constraint l i > 0 and the triangle inequalities, that the spectrum of<br />

this operator is discrete. In particular the mass gap, the spacing between the lowest<br />

eigenvalue and the first excited state, is of the same order as the ultraviolet cutoff.<br />

One can argue that this is in fact a general feature of the strong coupling theory,<br />

where one is far removed from a lattice continuum limit. The latter has to be taken<br />

in the vicinity of a non-trivial ultraviolet fixed point, if such a fixed point can be<br />

found. One would then anticipate that the excitation spectrum would become denser<br />

as one approaches the lattice continuum limit, in accordance with the existence of a<br />

massless spin two particle in this limit.<br />

Note that in the lattice theory the operator ordering ambiguity has not gone away<br />

either: in principle one would have to check that different orderings give the same<br />

physical results, whichever way those are defined (for example in terms of vacuum<br />

expectation values of invariant operators, or quantum correlations of invariant operators<br />

at fixed geodesic distance along the spatial directions).<br />

Irrespective of its specific form, it is in general possible to simplify the lattice<br />

Hamiltonian constraint in Eqs. (4.175) and (4.176) by using scaling arguments, as<br />

one does often in ordinary non-relativistic quantum mechanics. After setting for the<br />

scaled cosmological constant λ = 8πGλ 0 and dividing the equation out by common<br />

factors, it can be recast in the slightly simpler form<br />

{<br />

}<br />

−α a 6 1 · √<br />

g(l 2 ) G ij(l 2 ∂ 2<br />

) − β a 2 · 3R(l 2 )+1 Ψ[l 2 ]=0 , (4.180)<br />

∂l 2 i ∂l2 j<br />

where one finds it useful to define a dimensionless Newton’s constant, as measured<br />

in units of the cutoff Ḡ ≡ 16πG/a 2 , and a dimensionless cosmological constant λ ¯ 0 ≡<br />

λ 0 a 4 , so that in the above equation one has α = Ḡ/¯λ 0 and β = 1/Ḡλ ¯ 0 . Furthermore<br />

the edge lengths have been rescaled so as to be able to set λ 0 = 1 in lattice units (it is<br />

clear from the original gravitational action that the cosmological constant λ 0 simply<br />

multiplies the total spacetime volume, thereby just shifting around the overall scale<br />

for the problem). Schematically Eq. (4.176) is therefore of the form

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