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Feynman Path Integral Formulation

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206 6 Lattice Regularized Quantum Gravity<br />

are always positive due to the enforcement of the triangle inequalities. Thus from<br />

a practical point of view the barycentric volume subdivision is the simplest to deal<br />

with.<br />

φ 3<br />

l 2<br />

3<br />

A 23<br />

l 5<br />

A 24<br />

4<br />

φ 4<br />

A 13<br />

φ 1<br />

1<br />

A 11<br />

A 12<br />

l 1<br />

A 22<br />

l 4<br />

2<br />

l 3<br />

φ 2<br />

Fig. 6.16 More dual areas appearing in the scalar field action.<br />

The scalar action of Eq. (6.134) has a very natural form: it involves the squared<br />

difference of fields at neighboring points divided by their invariant distances (φ i −<br />

φ j )/l ij , weighted by the appropriate space-time volume element V (d)<br />

ij<br />

associated<br />

with the lattice link ij. This suggests that one could just as well define the scalar<br />

fields on the vertices of the dual lattice, and write<br />

(<br />

I(l 2 ,φ) = 1 2 ∑ V rs<br />

(d) φr − φ<br />

) s 2<br />

, (6.137)<br />

l rs<br />

<br />

with l rs the length of the edge connecting the dual lattice vertices r and s, and consequently<br />

V rs<br />

(d) the spacetime volume fraction associated with the dual lattice edge<br />

rs. One would expect both forms to be equivalent in the continuum limit.<br />

Continuing on with the two-dimensional case, mass and curvature terms such as<br />

the ones appearing in Eq. (6.124) can be added to the action, so that the total scalar<br />

lattice action contribution becomes<br />

I = 1 2<br />

∑<br />

<br />

A ij<br />

( φi − φ j<br />

l ij<br />

) 2<br />

+<br />

1<br />

2 ∑A i (m 2 + ξ R i )φi 2 . (6.138)<br />

i<br />

The term containing the discrete analog of the scalar curvature involves the quantity<br />

A i R i ≡ ∑ δ h ∼ √ gR . (6.139)<br />

h⊃i<br />

In the above expression for the scalar action, A ij is the area associated with the<br />

edge l ij , while A i is associated with the site i. Again there is more than one way to

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