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Feynman Path Integral Formulation

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7.4 Strong Coupling Expansion 245<br />

At the next order one has<br />

c 3 = Nh 3 [〈(δA)4 〉−4〈δA〉〈(δA) 3 〉−3〈(δA) 2 〉 2 + 12〈(δA) 2 〉〈δA〉 2 − 6〈δA〉 4 ]/6 ,<br />

(7.74)<br />

and so on. Note that the expressions in square parentheses become rapidly quite<br />

small, O(1/Nh n ) with increasing order n, as a result of large cancellations that must<br />

arise eventually between individual terms inside the square parentheses. In principle,<br />

a careful and systematic numerical evaluation of the above integrals (which is quite<br />

feasible in practice) would allow the determination of the expansion coefficients in<br />

k for the average curvature < δA > to rather high order.<br />

As an example, consider a non-analyticity in the average scalar curvature<br />

R(k) = < ∫ dx √ g(x)R(x) ><br />

< ∫ dx √ g(x) > ≈ < ∑ h δ h A h ><br />

< ∑ h V h > , (7.75)<br />

assumed for concreteness to be of the form of an algebraic singularity at k c , namely<br />

R(k)<br />

∼<br />

k→k c<br />

A R (k c − k) δ , (7.76)<br />

with δ some exponent. It will lead to a behavior, for the general term in the series<br />

in k, of the type<br />

(−1) n (δ − n + 1)(δ − n + 2)...δ<br />

A R<br />

n!kc<br />

n−δ k n . (7.77)<br />

Given enough terms in the series, the singularity structure can then be investigated<br />

using a variety of increasingly sophisticated series analysis methods.<br />

It can be advantageous to isolate in the above expressions the local fluctuation<br />

term, from those terms that involve correlations between different hinges. To see<br />

this, one needs to go back, for example, to the first order expression in Eq. (7.72)<br />

and isolate in the sum ∑ h the contribution which contains the selected hinge with<br />

value δA, namely<br />

∑<br />

h<br />

δ h A h = δ A + ∑<br />

′ δ h A h , (7.78)<br />

h<br />

where the primed sum indicates that the term containing δA is not included. The<br />

result is<br />

∫<br />

( ∫ 2<br />

dμ(l 2 )(δ A) 2 dμ(l 2 )δ A)<br />

c 1 = ∫<br />

− ( ∫<br />

dμ(l 2 2<br />

)<br />

dμ(l )) 2<br />

∫<br />

( ∫<br />

dμ(l 2 )δ A ∑<br />

′ δ h A h dμ(l 2 )δ A) ( )<br />

∫<br />

dμ(l 2 ) ∑<br />

′ δ h A h<br />

h<br />

h<br />

+ ∫<br />

−<br />

( ∫<br />

dμ(l 2 2<br />

.<br />

)<br />

dμ(l )) 2<br />

(7.79)

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