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Feynman Path Integral Formulation

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182 6 Lattice Regularized Quantum Gravity<br />

χ =<br />

d<br />

∑<br />

i=0<br />

(−1) i N i , (6.48)<br />

where N i is the number of simplices of dimension i. Also it should be noted that<br />

in two dimensions the compact action I com = ∑ p sinδ p does not satisfy the Gauss-<br />

Bonnet relation.<br />

In three dimensions the Regge lattice action reads<br />

I R = −k<br />

∑<br />

edges h<br />

l h δ h , (6.49)<br />

where δ h is the deficit angle around the edge labeled by h. Variation with respect to<br />

an edge length l h gives two terms, of which only the term involving the variation of<br />

the edge is non-zero<br />

δ I R = −k δl h · δ h . (6.50)<br />

∑<br />

edges h<br />

In fact it was shown by Regge that for any d > 2 the term involving the variation<br />

of the deficit angle does not contribute to the equations of motion (just as in the<br />

continuum the variation of the Ricci tensor does not contribute to the equations of<br />

motion either). Therefore in three dimensions the lattice equations of motion, in the<br />

absence of sources and cosmological constant term, reduce to<br />

δ h = 0 , (6.51)<br />

implying that all deficit angles have to vanish, i.e. a flat space.<br />

In four dimensions variation of I R with respect to the edge lengths gives the<br />

simplicial analogue of Einstein’s field equations, whose derivation is again, as mentioned,<br />

simplified by the fact that the contribution from the variation of the deficit<br />

angle is zero<br />

δ I R = δ(A h ) · δ h . (6.52)<br />

∑<br />

triangles h<br />

In the discrete case the field equations reduce therefore to<br />

∂V s<br />

λ 0 ∑<br />

s<br />

∂l ij<br />

− k ∑<br />

h<br />

δ h<br />

∂A h<br />

∂l ij<br />

= 0 , (6.53)<br />

and the derivatives can then be worked out for example from Eq. (6.5). Alternatively,<br />

a rather convenient and compact expression can be given (Hartle, 1984) for the<br />

derivative of the squared volume V 2 n of an arbitrary n-simplex with respect to one of<br />

its squared edge lengths<br />

∂V 2 n<br />

∂l 2 ij<br />

= 1 n 2 ω n−1 · ω ′ n−1 , (6.54)

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