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Feynman Path Integral Formulation

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264 7 Analytical Lattice Expansion Methods<br />

Fig. 7.12 Cross polytope<br />

β n with n = 8and2n = 16<br />

vertices, whose surface can<br />

be used to define a simplicial<br />

manifold of dimension d =<br />

n − 1 = 7. For general d, the<br />

cross polytope β d+1 will have<br />

2(d + 1) vertices, connected<br />

to each other by 2d(d + 1)<br />

edges.<br />

δ d = 0 + 4 d − ( ε d,d+1 + 3terms + ε 1,d ε 1,d+1 + ... ) + ... (7.144)<br />

and therefore close to flat in the large d limit (due to our choice of an equilateral<br />

starting configuration). Indeed if the choice of triangulation is such that the deficit<br />

angle is not close to zero, then the discrete model leads to an average curvature<br />

whose magnitude is comparable to the lattice spacing or ultraviolet cutoff, which<br />

from a physical point of view does not seem very attractive: one obtains a spacetime<br />

with curvature radius comparable to the Planck length.<br />

When evaluated on such a manifold the lattice action becomes<br />

√<br />

d 2<br />

d/2<br />

2 ( λ 0 − kd 3) [ 1 − 1 d!<br />

8 ∑ εij 2 + 1 ( 1<br />

d 4 ∑ ε ij + 1 ) ]<br />

8 ∑ ε ij ε ik + O(1/d 2 ) .<br />

(7.145)<br />

Dropping the 1/d correction the action is proportional to<br />

(<br />

λ0 − kd 3) ∑εij 2 . (7.146)<br />

− 1 2<br />

Since there are 2d(d + 1) edges in the cross polytope, one finds therefore that, at<br />

the critical point kd 3 = λ 0 , the quadratic form in ε, defined by the above action,<br />

develops 2d(d + 1) ∼ 2d 2 zero eigenvalues.<br />

This result is quite close to the d 2 /2 zero eigenvalues expected in the continuum<br />

for large d, with the factor of four discrepancy presumably attributed to an underlying<br />

intrinsic ambiguity that arises when trying to identify lattice points with points<br />

in the continuum.<br />

It is worth noting here that the competing curvature (k) and cosmological constant<br />

(λ 0 ) terms will have comparable magnitude when<br />

k c = λ 0 l 2 0<br />

d 3 . (7.147)

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