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Feynman Path Integral Formulation

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5.2 Semiclassical Expansion 147<br />

with θ ranging from 0 to π, r 0 = √ 3/λ and a < r 0 . For sufficiently small boundary<br />

three-geometries, a ≪ r 0 , the metric interior to the boundary approaches that of<br />

Euclidean flat space (with θ → t),<br />

ds 2 = dt 2 + t 2 ĝ ij dφ i dφ j . (5.21)<br />

In this limit one would expect therefore that a calculation of the quantum corrections<br />

could be carried out in a flat background with λ = 0, with higher order corrections<br />

then involving the ratio between the two radii in question, O(a 2 /r0 2 ). Then in the<br />

expansion of the metric of Eq. (5.10) one just has g μν = η μν , the flat metric.<br />

The first step in such a program is therefore a re-writing of the expansion of<br />

the Euclidean action to quadratic order in the h field, and specifically of Î 2 [h] in<br />

Eqs. (5.12) and (5.13), in terms of the quantities t and ĝ ij appearing in the metric in<br />

Eq. (5.21). One finds<br />

Î 2 [h] =− 1 ∫<br />

d 4 x { √ gp ij ∂ t h ij − H T − H L − h 00 C − h 0i C I } , (5.22)<br />

16πG<br />

with background three-metric g ij = t 2 ĝ ij , √ g the square root of the determinant of<br />

this g ij , π ij = √ gp ij the momentum conjugate to the quantum fluctuation h ij , and<br />

H T = √ [<br />

)]<br />

g p ij p ij + 2t −1 p ij h ij − 1 4<br />

(∇ k h ij ∇ k h ij + 2t −2 h ij h ij<br />

H L = 1 √<br />

[<br />

2 g p i i p j j + t−1 p i ih j j<br />

+ 1 2<br />

(∇ k h j j ∇k h j j + 2∇ ih ij (∇ k h k j − ∇ j h k k ) − 1 2 7t−2 (h i i) 2)]<br />

C = 1 √<br />

[<br />

]<br />

2 g ∇ i ∇ j h ij − ∇ k ∇ k h i i + 2t −1 p i i − 1 2 5t−2 h i i<br />

C i = − √ [<br />

]<br />

g 2∇ j p ji − t −1 ∇ i h j j<br />

. (5.23)<br />

The metric components h 00 and h 0i act as Lagrange multiplier, giving four constraints<br />

C = 0 C i = 0 . (5.24)<br />

The physical subspace is obtained by imposing a gauge condition, in the case at hand<br />

one that leads to a substantial simplification of the problem. The gauge condition is<br />

∇ i h ij = 0 h i i = 0 , (5.25)<br />

and restricts the functional integration over transverse-traceless (TT) modes only.<br />

Due the decomposition of Î 2 in Eq. (5.22) into transverse and longitudinal contributions,<br />

H L only contains longitudinal and trace parts, and therefore vanishes.<br />

In the physical phase space spanned by the p (π ij<br />

TT ≡ √ gp ij<br />

TT<br />

) and q (hTT ij )variables<br />

one has<br />

∫<br />

P[a] =<br />

[dπ ij<br />

TT ][dhTT ij ] exp { −Î 2 (π TT ,h TT ) } , (5.26)

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