Tehnička termodinamika - Kemijsko-tehnološki fakultet

TEHNIČKA TERMODINAMIKA______________________________________________
a) kompresija se odvija izotermno
b) kompresija se odvija adijabatski.
Rješenje
a)
za T = konst.
b)
v2
v1
2
p1
=
p2
v = v
1
T 2 = T 1
v
v
2
1
w
p
p
1
2
R ⋅T1
8.314
⋅ 303
3 −1
v 2 = = = 0.089 m kg
p 2 29 ⋅ 980.7
→ ∆u = 0
p
8.314
98.07
1
−1
1,2
= R ⋅T
ln = ⋅ 303⋅
2.3log = −200 kJ kg
p2
29
980.7
⎛ p
= ⎜
⎝ p
1
2
⎞
⎟
⎠
1
κ
→
v
⎛
p
⎞
1
2 = v1
⎜
⎟ ⎝ p2
⎠
1
κ
1
κ
1
8.314
⋅ 303 ⎛ 1 ⎞1.4
3 −1
R ⋅T1
⎛ p1
⎞
v 2 =
⎜
⎟ = ⋅ ⎜ ⎟ = 0.177 m kg
p1
⎝ p2
⎠ 29 ⋅ 98.07 ⎝10
⎠
T
T
2
1
κ −1
⎛ p2
⎞ κ
= ⎜
⎟
⎝ p 1 ⎠
T
κ −1
0.4
⎛ p2
⎞ κ
303 101.
4
2 = T1
⎜ ⎟ = ⋅ =
⎜
⎝ p
1
⎟
⎠
585 K
100