Tehnička termodinamika - Kemijsko-tehnološki fakultet

_________________________________________________Drugi glavni zakon termodinamike
Ukupna masa dušika
mCO = ωCO
⋅ ms,2
= 0.25 ⋅1.784
= 0.446kg
m ω ⋅ m = 0.75 ⋅1.784
= 1.338kg
= N s,2
N2
2
mN = 0.8358 + 1.338 =
2
2.1738kg
mH2
0.0279
ω H = = = 0.009
2
m s 3.177
ω
m
0.5293
=
3.177
CO2
CO =
=
2
m s
0.166
mN2
2.1738
ω N = = = 0.685
2
m s 3.177
mCO
0.446
ω CO = = = 0.141
m s 3.177
c p,
s
c p, s
c p ∑ ⋅ c
= n
, s ωi
i=
1
= ω H ⋅ c
2 p, H + ω CO ⋅ c
2 2 p, CO + ω
2 N ⋅ c
2 p + ω
N CO ⋅ c p, CO
2
= 0.009 ⋅
29.31
2
+ 0.166 ⋅
c p, s =
36.08
44
1.132 kJ kg
p,
i
29.31
+ 0.685 ⋅ + 0.141⋅
28
−1
K
−1
29.31
28
R s
R s ∑ω
⋅ R
= n
i=
1
R s = ω ⋅ RH
+ ωCO
⋅ RCO
+ ω N ⋅ RN
+ ωCO
⋅ RCO
H2
2 2 2 2 2
8.314 8.314 8.314 8.314
= 0.009
⋅ + 0.166 ⋅ + 0.685 ⋅ + 0.141⋅
2
44
28
28
R s
0.312 kJ kg
−1 K
−1
=
−1
−1
cv, s = c p,
s − Rs
= 1.132 − 0.312 = 0.82 kJ kg K
i
i
189