Tehnička termodinamika - Kemijsko-tehnološki fakultet

TEHNIČKA TERMODINAMIKA__________________________________________
Rješenje
W
max.
= U
1
−U
2
− T
s
0
⋅
( s − s ) + p ⋅ ( V −V
)
1
m = m + m
2
s, 1 s,2
p1
⋅V1
ms,1
=
Rs,1
⋅T1
R s ∑ ⋅ R
= n
, 1 ωi
i=
1
R s , 1 = ω H ⋅ R + ω ⋅ R + ω ⋅ R
8.314
2
2 H2
CO2
CO2
N2
N2
8.314
44
−1
−1
R s, 1 = 0.02 ⋅ + 0.38 ⋅ + 0.60 ⋅ = 0.333 kJ kg K
2 −
2.65 ⋅10
⋅ 700 ⋅10
=
0.333 ⋅ 400
i
0
8.314
28
3
ms, 1
=
m
s,2
p
=
R
2
s,2
⋅V
2
⋅T
2
R s ∑ ⋅ R
= n
, 2 ωi
i=
1
i
1
1.393 kg
R s , 2 = ω CO ⋅ RCO
+ ω N 2
⋅ RN 2
8.314
28
8.314
28
−1
−1
R s, 2 = 0.25 ⋅ + 0.75 ⋅ = 0.297 kJ kg K
2 −
2.65 ⋅10
⋅ 800 ⋅10
=
0.297 ⋅ 400
3
ms, 2
=
ms
Sastav smjese nakon miješanja
= 1 .393 + 1.784 = 3.177 kg
1.784 kg
m ω ⋅ m = 0.02 ⋅1.393
= 0.0279 kg
= H s,1
H2
2
m ω ⋅ m = 0.38 ⋅1.393
= 0.5293 kg
CO =
2 CO2
s,1
m ω ⋅ m = 0.60 ⋅1.393
= 0.8358 kg
= N s,1
N2
2
2
188