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Science of Water : Concepts and Applications

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76 The <strong>Science</strong> <strong>of</strong> <strong>Water</strong>: <strong>Concepts</strong> <strong>and</strong> <strong>Applications</strong><br />

where<br />

r H = hydraulic radius<br />

A = cross-sectional area <strong>of</strong> the water<br />

P = wetted perimeter<br />

Why is hydraulic radius important? Good question.<br />

Probably the best way in which to answer this question is by illustration. Consider, for example,<br />

that in open channels it is <strong>of</strong> primary importance to maintain the proper velocity. This is the case,<br />

<strong>of</strong> course, because if velocity is not maintained then fl ow stops (theoretically). In order to maintain<br />

velocity at a constant level, the channel slope must be adequate to overcome friction losses. As with<br />

other fl ows, calculation <strong>of</strong> head loss at a given fl ow is necessary, <strong>and</strong> the Hazen–Williams equation<br />

is useful (Q = 0.435Cd 2.63S 0.54 ). Keep in mind that the concept <strong>of</strong> slope has not changed. The difference?<br />

We are now measuring, or calculating for, the physical slope <strong>of</strong> a channel (ft/ft), equivalent<br />

to head loss.<br />

The preceding seems logical, makes sense—but there is a problem. The problem is with the<br />

diameter. In conduits that are not circular (grit chambers, contact basins, streams <strong>and</strong> rivers), or in<br />

pipes only partially full (drains, wastewater gravity mains, sewers, etc.) where the cross-sectional<br />

area <strong>of</strong> the water is not circular, there is no diameter.<br />

If there is no diameter (<strong>and</strong> there is not), then what do we do? Another good question.<br />

Because there is no diameter in a situation where the cross-sectional area <strong>of</strong> the water is not<br />

circular, we must use another parameter to designate the size <strong>of</strong> the cross section, <strong>and</strong> the amount<br />

<strong>of</strong> it that contacts the sides <strong>of</strong> the conduit. This is where the hydraulic radius (rH ) comes in. The<br />

hydraulic radius is a measure <strong>of</strong> the effi ciency with which the conduit can transmit water. Its value<br />

depends on pipe size <strong>and</strong> amount <strong>of</strong> fullness. Simply stated, we use the hydraulic radius to measure<br />

how much <strong>of</strong> the water is in contact with the sides <strong>of</strong> the channel, or how much <strong>of</strong> the water is not<br />

in contact with the sides (see Figure 3.19).<br />

√ Note: For a circular channel fl owing either full or half-full, the hydraulic radius is (D/4).<br />

Hydraulic radii <strong>of</strong> other channel shapes are easily calculated from the basic defi nition.<br />

Hydraulic Depth<br />

The hydraulic depth is the ratio <strong>of</strong> area in fl ow to the width <strong>of</strong> the channel at the fl uid surface. (Note<br />

that another name for hydraulic depth is the hydraulic mean depth or hydraulic radius.)<br />

where<br />

d H = hydraulic depth<br />

A = area in fl ow<br />

w = width <strong>of</strong> the channel at the fl uid surface<br />

FIGURE 3.19 Hydraulic radius.<br />

d<br />

H <br />

A<br />

w<br />

Wetted perimeter Wetted area<br />

(3.24)

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