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Science of Water : Concepts and Applications

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364 The <strong>Science</strong> <strong>of</strong> <strong>Water</strong>: <strong>Concepts</strong> <strong>and</strong> <strong>Applications</strong><br />

where<br />

u = overfl ow rate, m3 (m2 d) or gpd/ft<br />

Q = average daily fl ow, m3 /d or gpd<br />

A = total surface area <strong>of</strong> basin, m2 or ft2 l <strong>and</strong> w = length <strong>and</strong> width <strong>of</strong> basin, m or ft<br />

√ Key Point: All particles having a settling velocity greater than the overfl ow rate will settle <strong>and</strong><br />

be removed.<br />

Hudson (1989) points out that rapid particle density changes due to temperature, solid concentration,<br />

or salinity can induce density current, which can cause severe short-circuiting in horizontal<br />

tanks.<br />

Example 10.66<br />

Problem:<br />

A water treatment plant has two clarifi ers treating 2.0 MGD <strong>of</strong> water. Each clarifi er is 14 ft wide, 80 ft<br />

long, <strong>and</strong> 17 ft deep. Determine: (a) detention time, (b) overfl ow, (c) horizontal velocity, <strong>and</strong> (d) weir<br />

loading rate assuming the weir length is 2.5 times the basin width.<br />

Solution:<br />

Step 1. Compute detention time (t) for each clarifi er.<br />

Step 2. Compute overfl ow rate u.<br />

2 mgd 1,000,000 gal 1ft1d Q <br />

2 d 7.48 gal 24h<br />

3<br />

5570 ft /h<br />

3<br />

92.8 ft /min<br />

() a<br />

Step 3. Compute horizontal velocity V.<br />

Step 4. Compute weir loading rate u w .<br />

V 14 ft 80 ft 17<br />

ft<br />

t <br />

3<br />

Q 5570 ft h<br />

1,000,000 gpd<br />

(b) u 893 gpd ft<br />

14 ft 80 ft<br />

Q<br />

<br />

<br />

lw <br />

3<br />

Q 92.8 ft min<br />

(c) V <br />

0.39 ftmin wd 14 ft 17<br />

ft<br />

Q 1,000,000 gpd<br />

(d) uw<br />

<br />

28,571 gpdft 25 .<br />

w 2.514 ft

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