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Science of Water : Concepts and Applications

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366 The <strong>Science</strong> <strong>of</strong> <strong>Water</strong>: <strong>Concepts</strong> <strong>and</strong> <strong>Applications</strong><br />

Solution:<br />

Example 10.69<br />

Flow rate, gpm <br />

total gallons produced<br />

filter run, min<br />

22,400,000<br />

gal<br />

<br />

(70 h)(60 min/h)<br />

5333 gpm<br />

Problem:<br />

At an average fl ow rate <strong>of</strong> 4000 gpm, how long a fi lter run (in hours) would be required to produce<br />

25 MG <strong>of</strong> fi ltered water?<br />

Solution:<br />

Write the equation as usual, fi lling in the known data:<br />

Then solve for x:<br />

Example 10.70<br />

Flow rate, gpm <br />

total gallons produced<br />

filter run, min<br />

25,000,000 gal<br />

4000 gpm <br />

( x h)(60 minh) 25,000,000 gal<br />

<br />

(4000)(60)<br />

104<br />

h<br />

Problem:<br />

A fi lter box is 20 ft × 30 ft (including the s<strong>and</strong> area). If the infl uent valve is shut, the water drops<br />

3.0 in./min. What is the rate <strong>of</strong> fi ltration in MGD?<br />

Solution:<br />

Given:<br />

Find the volume <strong>of</strong> water passing through the fi lter:<br />

Filter box = 20 ft × 30 ft<br />

<strong>Water</strong> drops = 3.0 in./min<br />

Volume = area × height<br />

Area = width × length<br />

√ Note: The best way to perform calculations for this type <strong>of</strong> problem is step by step, breaking<br />

down the problem into what is given <strong>and</strong> what is to be found.

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