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Science of Water : Concepts and Applications

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338 The <strong>Science</strong> <strong>of</strong> <strong>Water</strong>: <strong>Concepts</strong> <strong>and</strong> <strong>Applications</strong><br />

collision. Through experience, we see that effective mixing reduces the required amount <strong>of</strong> chemicals<br />

<strong>and</strong> greatly improves the sedimentation process, which results in longer fi lter runs <strong>and</strong> higher-<br />

quality fi nished water.<br />

The goal <strong>of</strong> fl occulation is to form a uniform, feather-like material similar to snowfl akes—<br />

a dense, tenacious fl oc that entraps the fi ne, suspended, <strong>and</strong> colloidal particles <strong>and</strong> carries them<br />

down rapidly in the settling basin.<br />

Polymers are <strong>of</strong>ten added to increase the speed <strong>of</strong> fl oc formation <strong>and</strong> the strength <strong>and</strong> weight<br />

<strong>of</strong> the fl oc.<br />

COAGULATION AND FLOCCULATION GENERAL CALCULATIONS<br />

In the proper operation <strong>of</strong> the coagulation <strong>and</strong> fl occulation unit processes, calculations are performed<br />

to determine chamber or basin volume, chemical feed calibration, chemical feeder settings,<br />

<strong>and</strong> detention time.<br />

Chamber <strong>and</strong> Basin Volume Calculations<br />

To determine the volume <strong>of</strong> a square or rectangular chamber or basin, use Equation 10.22<br />

or 10.23:<br />

3<br />

Volume, ft (length, ft)(width, ft)(depth, ft)<br />

(10.22)<br />

Volume, gal (length, ft)(width, ft)(depth, ft)(7.48 gal ft 3<br />

) (10.23)<br />

Example 10.23<br />

Problem:<br />

A fl ash mix chamber is 4 ft2 with water to a depth <strong>of</strong> 3 ft. What is the volume <strong>of</strong> water (in gallons) in<br />

the chamber?<br />

Solution:<br />

3<br />

Volume, gal (length, ft)(width, ft)(depth, ft) ( 7.48 galft) ( <br />

359 gal<br />

3<br />

4 ft)(4 ft)(3 ft)(7.48 gal ft )<br />

Example 10.24<br />

Problem:<br />

A fl occulation basin is 40 ft long, 12 ft wide, with water to a depth <strong>of</strong> 9 ft. What is the volume <strong>of</strong> water<br />

(in gallons) in the basin?<br />

Solution:<br />

Volume, gal length, ft)(width, ft)(depth, ft)(7.48 gal ft 3<br />

( )<br />

3<br />

( 40 ft)(12 ft)(9 ft)(7.48 galft) 32,314 gal

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