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Science of Water : Concepts and Applications

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<strong>Water</strong> Treatment Calculations 361<br />

The values <strong>of</strong> drag coeffi cient depend on the density <strong>of</strong> water ( p), relative velocity (u), particle<br />

diameter (d), <strong>and</strong> viscosity <strong>of</strong> water ( μ), which gives the Reynolds number R as:<br />

R pud<br />

(10.60)<br />

As the Reynolds number increases, the value <strong>of</strong> C D increases. For R < 2, C D is related to R by<br />

the linear expression as follows:<br />

CD<br />

24<br />

<br />

R<br />

(10.61)<br />

At low levels <strong>of</strong> R, the Stokes’ equation, for laminar fl ow conditions, is used (Equations 10.60<br />

<strong>and</strong> 10.61 substituted into 10.59).<br />

g( p) d<br />

u <br />

18<br />

2<br />

(10.62)<br />

In the region <strong>of</strong> higher Reynolds numbers (2 < R < 500–1000), C D becomes (Fair et al., 1968):<br />

CD<br />

24 3<br />

034<br />

. (10.63)<br />

R R<br />

√ Key Point: In the region <strong>of</strong> turbulent fl ow (500–1000 < R < 200,000), the C D remains approximately<br />

constant at 0.44.<br />

The velocity <strong>of</strong> settling particles results in Newton’s equation (AWWA & ASCE, 1990):<br />

⎡(<br />

ppp) gd⎤<br />

u 1.74<br />

⎢<br />

⎣ p<br />

⎥<br />

⎦<br />

05 .<br />

(10.64)<br />

√ Key Point: When the Reynolds number >200,000, the drag force decreases substantially <strong>and</strong><br />

C D becomes 0.10. There is no settling at this condition.<br />

Example 10.65<br />

Problem:<br />

Estimate the terminal settling velocity in water at a temperature <strong>of</strong> 21°C <strong>of</strong> spherical particles with<br />

specifi c gravity 2.40 <strong>and</strong> average diameter <strong>of</strong> (a) 0.006 mm <strong>and</strong> (b) 1.0 mm.<br />

Solution:<br />

Step 1. Use Equation 10.62 for (a).<br />

Given: At temperature (T) = 21°C<br />

ρ = 998 kg/m3 μ = 0.00098 N s/m2 d = 0.06 mm = 6 × 10 –5 m<br />

g = 9.81 m/s2

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