11.07.2015 Views

Boreskov Institute of Catalysis of the Siberian Branch of Russian ...

Boreskov Institute of Catalysis of the Siberian Branch of Russian ...

Boreskov Institute of Catalysis of the Siberian Branch of Russian ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

OP-V-21ESTIMATION OF OPTIMAL REACTOR VOLUMES FORBIOCATALYST PRODUCTION USING NLP FORMULATIONMarko Tramšek, Andreja GoršekUniversity <strong>of</strong> Maribor, Faculty <strong>of</strong> Chemistry and Chemical Engineering, Smetanova 17,SI–2000 Maribor, Slovenia, fax: ++386 2 252 77 74,e-mail: marko.tramsek@uni-mb.si, andreja.gorsek@uni-mb.siAbstractMany novel applications <strong>of</strong> kefir grains as biocatalyst or raw biomaterial in recent years(Plessas et al., 2005; Rimada and Abraham, 2001; Athanasiadis et al., 2001; Athanasiadis etal., 2004) require incorporating <strong>of</strong> economically efficient reactor systems into kefir grainsproduction processes. Traditionally, production operates in batch mode. However, <strong>the</strong>re areseveral well-known advantages for using continuous operation instead <strong>of</strong> batch one(Williams, 2002). Despite <strong>the</strong> promising idea <strong>of</strong> incorporating <strong>the</strong> continuous mode operationin classic kefir grains production, no research papers concerning this kind <strong>of</strong> design have beenpublished so far.Therefore, <strong>the</strong> main goal <strong>of</strong> <strong>the</strong> present study was to design a continuous multi-stagereactor system for kefir grains production. In order to minimize total volume <strong>of</strong> CSTRs, V T , inmulti-stage reactor system, for desired kefir grains capacity, q m,KG,pr , and final conversion inNth CSTR, X o,N , with regard to decreasing <strong>of</strong> fermentation medium pH, a NLP optimizationproblem has been formulated:min VTNj = 1( )( )( o, o,( −1))( o,( N−1))V = f X ; X = constant; N = 11 o,1 o,1V = f X ; N > 11 o,1j j jjV = f X ; N ≥ 2N=∑ VV = f X , X ; N > 2; 1 < j

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!