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Structural Concrete - Hassoun

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3.15 Analysis of T- and I-Sections 131<br />

Figure 3.32<br />

T-section analysis.<br />

The analysis of a T-section is similar to that of a doubly reinforced concrete section, considering<br />

an area of concrete (b e − b w )t as equivalent to the compression steel area A ′ s. The analysis is<br />

divided into two parts, as shown in Fig. 3.32:<br />

1. A singly reinforced rectangular basic section, b w d, and steel reinforcement A s1 .Thecompressive<br />

force, C 1 , is equal to 0.85 f ′ cab w , the tensile force, T 1 , is equal to A s1 f y , and the moment<br />

armisequaltod − a/2.<br />

2. A section that consists of the concrete overhanging flange sides 2 × [(b e − b w )t]/2 developing<br />

the additional compressive force (when multiplied by 0.85 f ′ c ) and a moment arm equal to<br />

d − t/2. If A sf is the area of tension steel that will develop a force equal to the compressive<br />

strength of the overhanging flanges, then<br />

A sf f y = 0.85f ′ c(b e − b w )t<br />

A sf = 0.85f ′ ct(b e − b w )<br />

f y<br />

(3.62)<br />

The total steel used in the T-section A s is equal to A s 1 + A sf ,or<br />

A s1 = A s − A sf (3.63)<br />

The T-section is in equilibrium, so C 1 = T 1 , C 2 = T 2 ,andC = C 1 + C 2 = T 1 + T 2 = T. Considering<br />

equation C 1 = T 1 for the basic section, then A s1 f y = 0.85 f ′ cab w or (A s − A sf )f y = 0.85<br />

f ′ cab w ; therefore,<br />

a = (A s − A sf )f y<br />

0.85f ′ cb w<br />

(3.64)

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