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Structural Concrete - Hassoun

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540 Chapter 15 Design for Torsion<br />

when the principal stress in concrete is about 4λ √ f ′ c. When T u > T cr , a torque equal<br />

to T cr Eq. 15.19, may be assumed to occur at the critical sections near the faces of the<br />

supports.<br />

The ACI Code limits the design torque to the smaller of T u from factored loads or φT cr from Eq.<br />

15.19.<br />

15.8.5 Limitation of Torsional Moment Strength<br />

The ACI Code, Section 22.7.7, limits the size of the cross-sectional dimension by the following<br />

two equations:<br />

1. For solid sections,<br />

) ( )<br />

√ 2 2 [( )<br />

√(<br />

Vu T<br />

+ u P h<br />

Vc<br />

≤ φ + 8 √ ]<br />

f<br />

b w d 1.7 A 2 c<br />

′ b<br />

oh<br />

w d<br />

(15.21)<br />

2. For hollow sections,<br />

) ( )<br />

T<br />

+ u P h<br />

b w d 1.7 A 2 oh<br />

(<br />

Vu<br />

[( )<br />

Vc<br />

≤ φ + 8 √ ]<br />

f c<br />

′ b w d<br />

(15.22)<br />

where V c equals 2λ √ f cb ′ w d, which is shear strength for normal-weight concrete. All other<br />

terms were defined in Section 15.8.2.<br />

This limitation is based on the fact that the sum of the stresses due to shear and torsion<br />

(on the left-hand side) may not exceed the cracking stress plus 8 √ f ′ c. The same condition was<br />

applied to the design of shear without torsion in Chapter 5. The limitation is needed to reduce<br />

cracking and to prevent crushing of the concrete surface due to inclined shear and torsion<br />

stresses.<br />

15.8.6 Hollow Sections<br />

Combined shear and torsional stresses in a hollow section are shown in Fig. 15.6, where the<br />

wall thickness is assumed constant. In some hollow sections, the wall thickness may vary around<br />

the perimeter. In this case, Eq. 15.22 should be evaluated at the location where the left-hand<br />

side is maximum. Note that at the top and bottom flanges, the shear stresses are usually negligible.<br />

In general, if the wall thickness of a hollow section t is less than A oh /P h , then Eq. 15.22<br />

becomes<br />

(ACI Code, Section 22.7.7).<br />

15.8.7 Web Reinforcement<br />

V u<br />

b w d +<br />

T u<br />

1.7A 0h t ≤ φ [(<br />

Vc<br />

b w d<br />

)<br />

+ 8 √ f ′ c<br />

]<br />

(15.23)<br />

As was explained earlier, the ACI Code approach for the design of the members due to torsion is<br />

based on the space truss analogy in Fig. 15.8. After torsional cracking, two types of reinforcement<br />

are required to resist the applied torque, T u : transverse reinforcement, A t , in the form of

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