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Structural Concrete - Hassoun

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CHAPTER23<br />

REVIEW PROBLEMS ON CONCRETE<br />

BUILDING COMPONENTS<br />

In order to achieve the desired strength of concrete in structural elements, it is particularly important<br />

to follow the proper procedure of determining member dimensions and the necessary reinforcement<br />

required. This chapter mainly focuses on the general process of designing various building components,<br />

such as slabs, beams, columns, and footings, with compliance to ACI Code 318-14. The first<br />

step is to calculate the required strength of each of these elements by multiplying the actual applied<br />

loads by load factors. These loads then develop external forces, such as bending moment, shear,<br />

axial forces, or torsion, depending on how these loads are being applied to the structure. Once the<br />

strength requirements are determined, the proper reinforcement, along with the appropriate dimensions<br />

of each element, can then be developed. The final design of structural elements must account<br />

for three main items: structural safety, deflection, and cracking conditions.<br />

Example 23.1<br />

A simply supported beam has a 30 ft span and carries a service uniform dead load of 2 K/ft (including<br />

self-weight) and a uniform live load of 0.5 K/ft.<br />

′<br />

Given: b = 14 in., d = 26 in., f c = 5ksi,f y = 60 ksi.<br />

a. Design the section for flexural reinforcement.<br />

b. Design for shear reinforcement.<br />

c. Check for development length.<br />

Solution:<br />

a. Design the section for flexural reinforcement<br />

Check for minimum thickness to satisfy the deflection criterion: (ACI Code, Section 24.2.3.1)<br />

Minimum thickness for simply supported beams =L16=30 × 1216 = 22.5 in. < 29 in. (OK)<br />

Determine the design moment strength: (ACI Code, Section 5.3.1)<br />

M u = 1.2M DL + 1.6M LL<br />

M u = 1.2 w DL × L2<br />

8<br />

+ 1.6 w LL × L2<br />

8<br />

M u = 1.2 2 × 302 0.5 × 302<br />

+ 1.6<br />

8<br />

8<br />

M u = 360 K ⋅ ft = 4, 320 K ⋅ in.<br />

945

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