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Structural Concrete - Hassoun

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8.6 Deep Members 315<br />

2. Check if beam is deep. Height of beam (h) is 4 ft, clear span (l n )is4ft.<br />

l n<br />

h = 4 2 = 2 < 4ft<br />

(Entire beam is in D − region)<br />

3. Calculate maximum shear strength of the beam cross section. Let V u at A be given as R A = 125 K<br />

and assume<br />

d = 0.9h = 0.9 × 48 = 43.2in., use 43 in.<br />

φV n = φ(10) √ √<br />

f c ′ b w d = 0.75(10) 4000(12)(43) =244 K > V u = 125 K (OK)<br />

4. Select a truss model. A triangular truss model is chosen. Assume that nodes act at the centerline<br />

of the supports and 4 in. from the lower and upper edges of the beam. The strut-and-tie model<br />

consists of a tie, BC, and two struts AB and AC.<br />

Let the angle between the strut and tie be θ = 60 ∘ > 25 ∘ OK.<br />

5. Calculate the forces in truss members.<br />

At the joint A (C–C–C) nodes:<br />

250 K<br />

F AB F AC<br />

F AB = F AC<br />

At joint B (C–C–T) nodes:<br />

F AB cos 30 ∘ = 250 K<br />

F AB = 250<br />

cos 30 ∘ = 144.34 K<br />

144.34 K<br />

F BC<br />

125 K<br />

F BC = 144.34 cos 60 = 72.17 K<br />

6. Check size of bearing:<br />

Effective strength of node A (C–C–C node) =0.85f c ′ φ<br />

Effective strength of node B, C (C–C–T node) =0.75f c ′<br />

P φ<br />

Bearing area required at node A = u<br />

0.85f c ′ φ = 250<br />

0.85 × 4 × 0.7 = 105in.2<br />

Bearing area required at nodes B and C =<br />

0.85f c ′ φ = 125<br />

0.75 × 4 × 0.7 = 60in.2<br />

Bearing area proposed = 8 ′′ × 8 ′′ = 64 in. 2 < 105 in. 2 (not safe)<br />

Since the width of beam is 12 ′′ , keep a “width with clear spacing 1.5” on both sides. The<br />

bearing pad length L is<br />

L = 105<br />

9 = 11.67′′<br />

Use 9 ′′ × 12 ′′ bearing pad at the load position and 8 ′′ × 8 ′′ bearing pad at support.<br />

P u

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