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Structural Concrete - Hassoun

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174 Chapter 4 Flexural Design of Reinforced <strong>Concrete</strong> Beams<br />

4.6 ADDITIONAL EXAMPLES<br />

The following design examples give some practical applications and combine structural analysis<br />

with concrete design of beams and frames.<br />

Example 4.10<br />

For the precast concrete I-section shown in Fig. 4.11, calculate the reinforcement needed to support a<br />

factored moment of 360 K⋅ft. Use f c ′ = 4ksi and f y = 60 ksi.<br />

Solution<br />

Determine if the force in the flange area 14 × 5 in. will be sufficient to resist a factored moment of 360<br />

K⋅ft. Let d = 23.5 in. Force in flange (C c )=0.85 × f c ′ (flange area) = 0.85 × 4 × (14 × 5) = 238 K located<br />

at 2.5 in. from the top fibers and a = 5in.:<br />

(<br />

φM n = 0.9C c d − a )<br />

23.5 − 2.5<br />

= 0.9 × 238 = 374.9K⋅ ft<br />

2<br />

12<br />

which is greater than the applied moment of 360 K⋅ft. Therefore, a < 5in.:<br />

(<br />

φM n = φA s f y d − 1 )<br />

2 a (<br />

)<br />

60A<br />

360 × 12 = 0.9A s (60) 23.5 −<br />

s<br />

1.7 × 14 × 14<br />

where<br />

a =<br />

A s f y<br />

0.85f c ′ b<br />

Solve to get A s = 3.79 in. 2 Or use Eq. 4.2 to get ρ = 0.01152 and A s = 0.01152 × 14 × 23.5 = 3.79 in. 2<br />

Use three no. 10 bars in one row, as shown in Fig. 4.11.<br />

For similar T-sections or I-sections, it is better to adopt a section with a flange size to accommodate<br />

the compression force, C c . In this case, a is less than or equal to the flange depth. The bottom flange is<br />

in tension and not effective.<br />

Figure 4.11 Example 4.10.

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