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Structural Concrete - Hassoun

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374 Chapter 11 Members in Compression and Bending<br />

where<br />

A = 0.85f ′ c<br />

b2<br />

B = 0.85f ′ c b(e′ − d)<br />

C = A ′ s (f y − 0.85f ′ c )(e′ − d + d ′ )+87A s e ′<br />

D =−87 A s e ′ β 1 d<br />

Once the values of A, B, C, andD are calculated, a can be determined by trial or directly<br />

by a scientific calculator. Also, the solution of the cubic equation can be obtained by using the<br />

well-known Newton–Raphson method. This method is very powerful for finding a root of f(x) = 0.<br />

It involves a simple technique, and the solution converges rapidly by using the following steps:<br />

1. Let f(a) = Aa 3 + Ba 2 + Ca + D, and calculate A, B, C, andD.<br />

2. Calculate the first derivative of f(a):<br />

f ′ (a) =3Aa 2 + 2Ba + C<br />

3. Assume any initial value of a, say,a 0 , and compute the next value:<br />

a 1 = a 0 − f (a 0)<br />

f ′ (a 0 )<br />

4. Use the obtained value a 1 in the same way to get<br />

a 2 = a 1 − f (a 1)<br />

f ′ (a 1 )<br />

5. Repeat the same steps to get the answer up to the desired accuracy. In the case of the analysis of<br />

columns when compression controls, the value a is greater than the balanced a(a b ). Therefore,<br />

start with a 0 = a b and repeat twice to get reasonable results.<br />

Example 11.5<br />

Repeat Example 11.4 using numerical solution.<br />

Solution<br />

1. Calculate A, B, C, andD and determine f(a):<br />

A = 0.85 × 4 × 14<br />

2 = 23.8<br />

B = 0.85 × 4 × 14(18.5 − 19.5) =−47.6<br />

C = 4(60 − 0.85 × 4)(18.5 − 19.5 + 2.5)+87 × 4 × 18.5<br />

= 6777.6<br />

D =−87 × 4 × 18.5 ×(0.85 × 19.5) =−106,710<br />

f (a) =23.8a 3 − 47.6a 2 + 6777.6a − 106,710<br />

2. Calculate the first derivative:<br />

f ′ (a) =71.4a 2 − 95.2a + 6777.6

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